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## Homework Statement

A voltmeter of resistance 50kΩ is used to measure the electric potential difference in a circuit, as shown. The cell has an electromotive force (emf) of 5.0 V and negligible internal resistance.

## Homework Equations

I=V/R

V=IR

## The Attempt at a Solution

I=5/150000 I=3.33E-5

V=50000*

**3.33E-5=1.7 V**

But the answer is 1 V. How?[/B]

But the answer is 1 V. How?