Finding current in circuit using Kirchoff's Rules

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Homework Help Overview

The discussion revolves around applying Kirchhoff's rules to find the current in a circuit. The original poster presents a circuit diagram and equations derived from Kirchhoff's Junction and Potential rules, expressing confusion over the resulting matrix and the number of independent equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive equations from the circuit loops but encounters a row of zeroes in their matrix, leading to questions about the independence of the equations. Some participants suggest that not all loops are independent and that an additional equation may be necessary from the junctions. The poster also questions whether currents can be equated across multiple batteries in the circuit.

Discussion Status

Participants are actively engaging with the original poster's confusion regarding the independence of the equations and the implications of Kirchhoff's rules. Guidance has been offered regarding the need for an additional equation and the treatment of currents across components, indicating a productive direction in the discussion.

Contextual Notes

The original poster's attempt is constrained by the number of independent loops in the circuit, which is under discussion. There is also a focus on the assumptions regarding current flow in relation to multiple batteries.

Zorba
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Homework Statement


[URL]http://img25.imageshack.us/i/circuitj.jpg[/URL]
(Image won't show up, here's the link http://img25.imageshack.us/i/circuitj.jpg/)

Homework Equations


Kirchoff's Junction & Potential rules.

The Attempt at a Solution


[URL]http://img29.imageshack.us/i/circuit2.jpg[/URL]
(Image won't show up, here's the link http://img29.imageshack.us/i/circuit2.jpg/)
Equations I get are:
(Loop1) [tex]-7I_2+4I_3 = 5[/tex]
(Loop2) [tex]-4I_2 - 2I_2 +2I_3 - 2I_4 = 8[/tex]
(Loop3) [tex]-6I_2 + 7.5I_3 - 2I_4 = 8[/tex]
(Loop4) [tex]-3I_2 - 4I_1 - 1.5I_3 = 5[/tex]

I made a matrix out of these then and row reduce them but, I don't have enough equations because I get a row of zeroes... which doesn't make sense to me, 4 equations, 4 unknowns and I don't see why applying Kirchoffs rules would make me end up with something like that... so I need to get another equation, but I was wondering if I've done wrong with the equations.
 
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Zorba said:
I made a matrix out of these then and row reduce them but, I don't have enough equations because I get a row of zeroes... which doesn't make sense to me, 4 equations, 4 unknowns and I don't see why applying Kirchoffs rules would make me end up with something like that... so I need to get another equation, but I was wondering if I've done wrong with the equations.

Hi Zorba! :smile:

There are 4 loops in your circuit, but only 3 of them are independent

so inevitably Kirchhoff (note the extra "h" :wink:) for one will be a linear sum of the others, which eventually reduces the matrix to zero! :biggrin:

Hint: yes you do need an extra equation, and you can get it from one of the junctions. :wink:
 
tiny-tim said:
Hi Zorba! :smile:

There are 4 loops in your circuit, but only 3 of them are independent

so inevitably Kirchhoff (note the extra "h" :wink:) for one will be a linear sum of the others, which eventually reduces the matrix to zero! :biggrin:

Hint: yes you do need an extra equation, and you can get it from one of the junctions. :wink:

Thanks, makes sense.

One last question, the current on either side of the batteries, can I equate them? Or can I only do this when there is only one battery in the circuit.
 
Zorba said:
One last question, the current on either side of the batteries, can I equate them? Or can I only do this when there is only one battery in the circuit.

Hi Zorba! :smile:

Yes, you can do this across any component …

basically it's because of conservation of charge … like water, the amount flowing in must equal the amount flowing out …

in terms of Kirchhoff's Rules you can look at a battery as a junction, with only two lines … the total current in those two lines must be the same! :biggrin:
 

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