# Finding current in circuit using Kirchoff's Rules

Zorba

## Homework Statement

[URL]http://img25.imageshack.us/i/circuitj.jpg[/URL]
(Image won't show up, here's the link http://img25.imageshack.us/i/circuitj.jpg/)

## Homework Equations

Kirchoff's Junction & Potential rules.

## The Attempt at a Solution

[URL]http://img29.imageshack.us/i/circuit2.jpg[/URL]
(Image won't show up, here's the link http://img29.imageshack.us/i/circuit2.jpg/)
Equations I get are:
(Loop1) $$-7I_2+4I_3 = 5$$
(Loop2) $$-4I_2 - 2I_2 +2I_3 - 2I_4 = 8$$
(Loop3) $$-6I_2 + 7.5I_3 - 2I_4 = 8$$
(Loop4) $$-3I_2 - 4I_1 - 1.5I_3 = 5$$

I made a matrix out of these then and row reduce them but, I don't have enough equations becuase I get a row of zeroes... which doesn't make sense to me, 4 equations, 4 unknowns and I don't see why applying Kirchoffs rules would make me end up with something like that... so I need to get another equation, but I was wondering if I've done wrong with the equations.

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Homework Helper
I made a matrix out of these then and row reduce them but, I don't have enough equations becuase I get a row of zeroes... which doesn't make sense to me, 4 equations, 4 unknowns and I don't see why applying Kirchoffs rules would make me end up with something like that... so I need to get another equation, but I was wondering if I've done wrong with the equations.

Hi Zorba!

There are 4 loops in your circuit, but only 3 of them are independent

so inevitably Kirchhoff (note the extra "h" ) for one will be a linear sum of the others, which eventually reduces the matrix to zero!

Hint: yes you do need an extra equation, and you can get it from one of the junctions.

Zorba
Hi Zorba!

There are 4 loops in your circuit, but only 3 of them are independent

so inevitably Kirchhoff (note the extra "h" ) for one will be a linear sum of the others, which eventually reduces the matrix to zero!

Hint: yes you do need an extra equation, and you can get it from one of the junctions.

Thanks, makes sense.

One last question, the current on either side of the batteries, can I equate them? Or can I only do this when there is only one battery in the circuit.