Using Kirchoff's Loop Rule to Determine Currents in a Circuit

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SUMMARY

The discussion focuses on applying Kirchoff's Loop Rule to determine the currents in a circuit involving resistors r_2 and R_3. The correct current through both resistors is I_3, as they are in series within that branch. Participants emphasize the importance of correctly formatting the equation, suggesting that terms should be grouped and include an equals sign for clarity. The problem statement specifies starting at node "a" and moving clockwise, which is crucial for accurate application of the loop rule.

PREREQUISITES
  • Understanding of Kirchoff's Loop Rule
  • Familiarity with circuit analysis terminology
  • Basic knowledge of series circuits
  • Ability to format equations correctly in physics problems
NEXT STEPS
  • Study the application of Kirchoff's Loop Rule in complex circuits
  • Learn about series and parallel resistor configurations
  • Practice formatting equations for clarity in physics homework
  • Explore common mistakes in circuit analysis and how to avoid them
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to improve their circuit analysis skills using Kirchoff's Loop Rule.

JessicaHelena
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Homework Statement


Screen Shot 2018-04-30 at 6.59.28 PM.png

Homework Equations



Kirchoff's Rule
The sum of all V = 0

The Attempt at a Solution


[/B]
I think I'm having a problem determining the current at r_2 and R_3. I had originally thought the currents at both resistors would be I_3, writing E_2 — r_2 I_3 — R_3 I_3 — I_1 R_1 = 0, but I got it wrong, so I thought that the current at both must've been I_1, getting the answer as screenshotted above, but that is wrong as well...
 

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JessicaHelena said:
I think I'm having a problem determining the current at r_2 and R_3. I had originally thought the currents at both resistors would be I_3, writing E_2 — r_2 I_3 — R_3 I_3 — I_1 R_1 = 0, but I got it wrong, so I thought that the current at both must've been I_1, getting the answer as screenshotted above, but that is wrong as well...
You are correct that the current through ##r_2## and ##R_3## is ##I_3## ; they are in series and only ##I_3## is in that branch of the circuit. Your answer in the above quote looks okay to me. Are there any special rules regarding the answer formatting that you might have overlooked? For example, do you need to enter a complete equation (with an equals sign), or group like current terms ( writing ##-~(r_2 + R_3)I_3## rather than ##-~r_2 I_3 - R_3 I_3## )?
 
The problem statement says "Apply the loop rule to loop aefgha". So my guess is they expect you to start at node "a" and go clockwise. So the first term would be +I1R1. The plus sign is optional.
 

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