Finding Displacement and Velocity at a Given Time

  • Thread starter Thread starter MiniOreo1998
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating displacement and velocity from given functions at a specific time, t=5. For the function A, s(t) = 3t + 7, the displacement at t=5 is 22 meters, and the velocity is constant at 3 m/s. For function B, s(t) = t³ - 2t² + 4t - 1, the displacement at t=5 is 94 meters, and the velocity is derived using calculus, resulting in a velocity of 43 m/s at t=5. The importance of applying calculus to find velocity from displacement is emphasized.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with polynomial functions and their properties.
  • Knowledge of displacement and velocity definitions in physics.
  • Ability to evaluate functions at specific points.
NEXT STEPS
  • Learn how to compute derivatives of polynomial functions to find velocity.
  • Study the relationship between displacement and velocity in kinematics.
  • Explore the application of calculus in real-world motion problems.
  • Practice evaluating functions and their derivatives at various points.
USEFUL FOR

Students studying calculus, physics enthusiasts, and anyone looking to understand the relationship between displacement and velocity in motion analysis.

MiniOreo1998
Messages
18
Reaction score
0

Homework Statement


For each function, find an expression for the velocity and the value of the displacement and velocity at t=5. Displacement is in metres and time is in seconds.

Homework Equations


A)[/B] s(t) = 3t + 7

B) s(t) = t3 - 2t2 + 4t - 1

The Attempt at a Solution



A) [/B]s(t) = 3t + 7
s(5) = 3(5) + 7
= 22 m/s

B) s(t) = t3 - 2t2 + 4t - 1
s(5) = 53 - 2(5) + 4(5) - 1
=94 m/s

 
Physics news on Phys.org
MiniOreo1998 said:

Homework Statement


For each function, find an expression for the velocity and the value of the displacement and velocity at t=5. Displacement is in metres and time is in seconds.

Homework Equations


A)[/B] s(t) = 3t + 7

B) s(t) = t3 - 2t2 + 4t - 1

The Attempt at a Solution



A) [/B]s(t) = 3t + 7
s(5) = 3(5) + 7
= 22 m/s

B) s(t) = t3 - 2t2 + 4t - 1
s(5) = 53 - 2(5) + 4(5) - 1
=94 m/s
s usually denotes position or displacement, not velocity. How do you find velocity from displacement?

Remember, the problem is asking you to find both displacement and velocity at a given time, t.

Hint: You posted this problem in the Calculus HW forum, yet you used no calculus. Didn't you find that a little odd?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
9
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
40
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K