1. The problem statement, all variables and given/known data a rigid body with a mass of 2 kg moves along a line due to a force that produces a position function x(t)= 4t^2, where x is measured in meters and t is measured in seconds. Find the work done during the first 5 seconds in two ways. 2. Relevant equations x(t)= 4t^2 Work is -> W = Integral from a to b of the force F(x) dx 3. The attempt at a solution SInce t is seconds, I tried plugging in 5 for the given eq. of x(t) = 4t^2 So I got x(5) = 4(5)^2 = 4(25)= 100 m So then I attempted integrating 4t^2 from time 0 to time 5 and got a completely different answer. Help anyone? Thanks!