Finding Dissociation energy , path of the particle involved

Click For Summary
SUMMARY

The discussion focuses on calculating the energy released during the dissociation of excited H2 molecules into two H-atoms. Initially, the H2 molecules have a kinetic energy of 1 eV, and after dissociation, one H-atom moves perpendicularly with a kinetic energy of 0.8 eV. The key to solving the problem lies in applying the conservation of momentum to analyze the momentum vectors of the H2 molecule and the resulting H-atoms, ultimately determining the energy difference between the initial and final states.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Familiarity with kinetic energy calculations
  • Basic knowledge of molecular dissociation processes
  • Ability to analyze vector components in physics
NEXT STEPS
  • Study conservation of momentum in two-body systems
  • Learn about kinetic energy transformations in molecular physics
  • Explore vector analysis techniques for momentum calculations
  • Investigate the principles of molecular dissociation and energy release
USEFUL FOR

Students in physics, particularly those studying molecular dynamics, as well as educators and researchers interested in energy transformations during molecular dissociation reactions.

imvaibhav
Messages
9
Reaction score
0

Homework Statement


Beam of excited H2 molecules travels in z direction, kinetic energy 1 eV.Then they decay & dissociate into 2 H-atoms.When one of the H atom has its final velocity perpendicular to z axis, its kinetic energy is always 0.8eV. Then what is the energy released in dissociative reaction?
.

Homework Equations


The Attempt at a Solution


How does the path effect the energy?
I am totally clueless about the question (Actually its not my homework problem, i came across it somewhere.
Any useful hint or the theory would also help.)Hoping to get replies..
 
Physics news on Phys.org
imvaibhav said:

Homework Statement


Beam of excited H2 molecules travels in z direction, kinetic energy 1 eV.Then they decay & dissociate into 2 H-atoms.When one of the H atom has its final velocity perpendicular to z axis, its kinetic energy is always 0.8eV. Then what is the energy released in dissociative reaction?
.

How does the path effect the energy?
You have to first apply conservation of momentum. Draw the vector of the momentum of the H2 molecule. Then draw the momentum vector of the H atom that is moving perpendicular to the z axis. What does the difference between these two vectors represent? (Hint: what does the momentum of the other H atom and the momentum of H atom moving perpendicular to the z axis add up to?).

Once you have the momentum vectors worked out, work out the energy of the two H atoms and compare it to the energy of the H2. Are they the same?

AM
 

Similar threads

Dissociation energy of two particles-variables only equation-mastering physics
  • · Replies 3 ·
Replies
3
Views
15K
Potential energy of particle in gravitational field of disk
  • · Replies 3 ·
Replies
3
Views
3K
Energy analysis of a particle moving in a shrinking circle
  • · Replies 17 ·
Replies
17
Views
4K
Problem involving energy/motion
  • · Replies 19 ·
Replies
19
Views
3K
Conceptual question about binding energy, from OCR paper
  • · Replies 4 ·
Replies
4
Views
2K
Minimum Kinetic energy of the hydrogen atom
  • · Replies 22 ·
Replies
22
Views
4K
Beta Spectroscopy: Decay Path of Na 22 and Sr 90 | Experimental Setup & Results
  • · Replies 1 ·
Replies
1
Views
3K
Calculating the Travel Time of High-Energy Particles Across Our Galaxy
  • · Replies 1 ·
Replies
1
Views
2K
Kinetic Energy of a Particle in a semi-spherical bowl
  • · Replies 2 ·
Replies
2
Views
2K
Find the potential energy of the particle
  • · Replies 3 ·
Replies
3
Views
2K