Finding Dissociation energy , path of the particle involved

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imvaibhav
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Homework Statement


Beam of excited H2 molecules travels in z direction, kinetic energy 1 eV.Then they decay & dissociate into 2 H-atoms.When one of the H atom has its final velocity perpendicular to z axis, its kinetic energy is always 0.8eV. Then what is the energy released in dissociative reaction?
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Homework Equations


The Attempt at a Solution


How does the path effect the energy?
I am totally clueless about the question (Actually its not my homework problem, i came across it somewhere.
Any useful hint or the theory would also help.)Hoping to get replies..
 
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imvaibhav said:

Homework Statement


Beam of excited H2 molecules travels in z direction, kinetic energy 1 eV.Then they decay & dissociate into 2 H-atoms.When one of the H atom has its final velocity perpendicular to z axis, its kinetic energy is always 0.8eV. Then what is the energy released in dissociative reaction?
.

How does the path effect the energy?
You have to first apply conservation of momentum. Draw the vector of the momentum of the H2 molecule. Then draw the momentum vector of the H atom that is moving perpendicular to the z axis. What does the difference between these two vectors represent? (Hint: what does the momentum of the other H atom and the momentum of H atom moving perpendicular to the z axis add up to?).

Once you have the momentum vectors worked out, work out the energy of the two H atoms and compare it to the energy of the H2. Are they the same?

AM