Finding distance east given west dist., velocities, and average velocity

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Homework Help Overview

The discussion revolves around calculating the distance traveled east given a known distance traveled west, along with respective velocities and average velocity. The problem involves understanding the relationships between distance, time, and velocity in a kinematic context.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculations involving total time and average velocity, questioning the handling of signs and simplification of terms. There is an attempt to derive the eastward distance based on the established relationships.

Discussion Status

Some guidance has been provided regarding the simplification of terms, and participants are actively engaging with the calculations. There appears to be a productive exploration of the relationships between the variables involved, although explicit consensus on the final outcome has not been reached.

Contextual Notes

Participants are navigating through the complexities of the problem, including potential sign errors and the implications of their calculations on the final distance. The discussion reflects a collaborative effort to clarify and verify the steps taken in the problem-solving process.

Alexandra Fabiello
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Homework Statement
You walk for 6.44 km with at a constant velocity of 2.51 m/s due west, turn around, and then walk with an average velocity of 0.495 m/s due east. From your starting point to your destination, your overall average velocity is 1.28 m/s due west. During the trip, how far east did you walk?
Hint: There are a number of issues to think about in this problem: The average velocity is the displacement, from initial point to final point, divided by the total time. Set up an equation for the average velocity in terms of the initial and final position and the total time. You can find the time it takes to walk west from the distance and velocity. You will need to substitute expressions for the velocity of each segment into the expression for the average velocity. Watch signs of positions and velocities, and unit conversions.
Relevant Equations
v = change in displacement/change in time
distance = velocity * time
av * total time = (west velocity * west time) - (east velocity * east time)
6.44 km * 1000 = 6440 m/2.51 m/s = 2565.737052 s = west time

av = (6440 m + - east distance)/(2565.737052 s + east time)

2565.737052 s + east time = total time

1.28 m/s * total time = (6440 m) - (0.495 m/s * east time)

1.28 m/s * (2565.737052 s + east time) = (6440 m) - (0.495 m/s * east time)

3284.143426 m +1.28 m/s(east time) - 6440 m = - (0.495 m/s * east time)

3155.856574 m = (0.495 m/s * east time) - 1.28 m/s(east time)

And now I'm stuck because it seems multiplying out will end up with lots of 'east time's and I'm not sure how to convert properly.
 
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You are almost there. You dropped a sign at this step, though.
Alexandra Fabiello said:
3155.856574 m = (0.495 m/s * east time) - 1.28 m/s(east time)
If you had
$$0.495t_{east}+1.28t_{east}$$
how would you simplify it?
 
teast(0.495 m/s + 1.28 m/s) = teast(1.775 m/s)

So 3155.856574 m /1.775 m/s = teast = 1777.947366 s going east

1777.947366 s * 0.495 m/s = 880.083946 m walked east = 8.80*102 m walked east rounded to 3 significant figures.

Right?

Thank you so much. Missed the obvious, but that's why I come here sometimes. Thanks again.
 
Alexandra Fabiello said:
teast(0.495 m/s + 1.28 m/s) = teast(1.775 m/s)

So 3155.856574 m /1.775 m/s = teast = 1777.947366 s going east

1777.947366 s * 0.495 m/s = 880.083946 m walked east = 8.80*102 m walked east rounded to 3 significant figures.

Right?

Thank you so much. Missed the obvious, but that's why I come here sometimes. Thanks again.
Yes
 

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