How Far Will a Block Travel Up a 32-Degree Ramp with Initial Speed of 3.7 m/s?

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A block with an initial speed of 3.7 m/s is traveling up a frictionless ramp angled at 32 degrees. To determine how far it will travel, two approaches can be used: kinematic equations or conservation of energy. A free body diagram is essential to find the acceleration, which allows for calculations without needing the mass of the block, as it will cancel out. The key is to derive the acceleration from the angle of the ramp and gravitational force. Understanding these principles will lead to the correct solution for the distance traveled up the ramp.
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Homework Statement


A block is given an initial speed of 3.7 m/s up a frictionless plane angled at 32 degrees. How far up the ramp will the block travel

Homework Equations


v^2 = v null^2 +2a delta x

The Attempt at a Solution


3.7^2 -0^2/(2*9.8) =x
my biggest issue is that i wasn't given a mass, and i can't find it using any of the formulas i know since i also don't have the force. I feel like I am using the wrong formula since I am not using the angle at all. [/B]
 
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Hi Cantphysics,

Welcome to Physics Forums.

There are two approaches. One using the kinematic equations where you'll need to draw a free body diagram for the block on the ramp to determine the acceleration. You'll find that the mass variable will eventually cancel out so you don't need a value for it. The other approach is to use conservation of energy. Again the mass will cancel out.
 
Notice that the only data you have not been explicitly given is the acceleration. To find that, you will need to follow the procedure suggested gneill in post #2
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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