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a.d.d92
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41.58m?
Finding distance using acceleration and time
- Thread starter a.d.d92
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- Acceleration Time
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A car accelerates from rest at 4.2 m/s² for 6.0 seconds, coasts for 2.3 seconds, and then decelerates at 3.3 m/s² until it stops. The total distance between the stop signs is calculated using the equations of motion, with the first stage yielding 75.6 meters. The second stage involves maintaining a constant speed, resulting in a distance of 57.96 meters. The final stage, where the car decelerates, is calculated to be approximately 96.21 meters. The total distance traveled is 229.77 meters.