Finding electric field with a changing linear charge density

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To find the electric field at point P due to a thin rod with a linearly varying charge density, the charge element dq is expressed as dq = λ dx, where λ = λ0 ((x-d)^3)/d^3. The electric field contribution dE is derived using the formula dE = k dq/r^2, with r being the distance from the charge element to point P. The integral to solve for the total electric field involves E = (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx. Clarification is provided that the distance r should be simply x, not L+d-x, indicating a minor correction in the approach.
bosteador3
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Homework Statement



a thin rod of length L is set along an X axis. we want to find the electric field at a point P at the origin, a distance "d" from the rod. The linear change density changes with X and it's given by λ=λ0 ((x-d)^3)/d^3 find the electric field at the point P...

(P)|---d---| |--------------L-----------------|

L is the length of the rod, d is just a distance from the rod to the point P. P is at the origin (x=0)


Homework Equations



λ=λ0 ((x-d)^3)/d^3

dq=λ dx

The Attempt at a Solution



i put q/x on differential form to get dq=lambda dx do i get dE=kdq/r^2 ,(L+ d - x)^2 => E= (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx... idk if I am wrong or what but i don't know how to solve that integral, i'd appreciate some help on this problem.
 
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bosteador3 said:

The Attempt at a Solution



i put q/x on differential form to get dq=lambda dx do i get dE=kdq/r^2 ,(L+ d - x)^2 => E= (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx... idk if I am wrong or what but i don't know how to solve that integral, i'd appreciate some help on this problem.

The distance r from a charge element dq to the origin would simply be x, not L+d-x. Looks good otherwise.
 
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