Finding electric field with a changing linear charge density

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SUMMARY

The discussion focuses on calculating the electric field at point P, located at the origin, due to a thin rod with a length L and a linearly varying charge density described by λ=λ0 ((x-d)^3)/d^3. The user attempts to derive the electric field using the differential charge element dq=λ dx and the formula dE=kdq/r^2. The integral to solve for the electric field involves the expression E= (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx. A correction is noted regarding the distance r from the charge element dq to the origin, which should be x instead of L+d-x.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of electrostatics, including Coulomb's law
  • Concept of linear charge density and its applications
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn integration techniques for solving complex integrals in physics
  • Explore the application of Coulomb's law in varying charge scenarios
  • Investigate the concept of electric field lines and their significance
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Students studying electromagnetism, physics educators, and anyone interested in advanced electrostatics problems involving variable charge densities.

bosteador3
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Homework Statement



a thin rod of length L is set along an X axis. we want to find the electric field at a point P at the origin, a distance "d" from the rod. The linear change density changes with X and it's given by λ=λ0 ((x-d)^3)/d^3 find the electric field at the point P...

(P)|---d---| |--------------L-----------------|

L is the length of the rod, d is just a distance from the rod to the point P. P is at the origin (x=0)


Homework Equations



λ=λ0 ((x-d)^3)/d^3

dq=λ dx

The Attempt at a Solution



i put q/x on differential form to get dq=lambda dx do i get dE=kdq/r^2 ,(L+ d - x)^2 => E= (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx... idk if I am wrong or what but i don't know how to solve that integral, i'd appreciate some help on this problem.
 
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bosteador3 said:

The Attempt at a Solution



i put q/x on differential form to get dq=lambda dx do i get dE=kdq/r^2 ,(L+ d - x)^2 => E= (k*λ)/d^3 ∫(x-d)^3/(L+d-x)^2 dx... idk if I am wrong or what but i don't know how to solve that integral, i'd appreciate some help on this problem.

The distance r from a charge element dq to the origin would simply be x, not L+d-x. Looks good otherwise.
 

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