Finding Energy in FCC Lattice Using Weak Potential Method

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The degeneracy of the FCC lattice is determined to be 12, which can be calculated by counting the distinct points in the first Brillouin zone. To find the energy of an electron in this lattice using the weak potential method, one would typically need to solve a 12th-degree equation. However, by utilizing the symmetry of the FCC lattice, the problem can be simplified to an 8th-degree equation through a technique called the 'decoupling approximation.' This method involves splitting the lattice into two sublattices and decoupling the equations for each. This approach makes the calculation more manageable while still accurately determining the energy.
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Homework Statement
Find the energy of an electron in a FCC lattice using the weak potential method.
Relevant Equations
\[(E^0_{(k+G)}+V_0-E_k)u_G(k) + \sum_{G'\ne G}u_{G'}(k)=0\]
I have a problem with finding the energy of an electron in an FCC lattice using the weak potential method. We did that for a one-dimensional lattice during class, and I know that there was a double degeneration at the boundaries of the first Brillouin Zone. However, I'm not sure what degeneration there is in the FCC lattice. I think 8 but that would mean I would have to find a determiner of a 8x8 matrix and then solve an 8th degree equation in order to find the energy which is kind of a scary thing to do.
So, how to find the energy?
 
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What degeneration does the FCC lattice have?The degeneracy of the FCC lattice is 12. You can calculate this by counting the number of distinct points in the first Brillouin zone (12). To find the energy, you will need to solve a 12th-degree equation, but there is a simpler way to do this. By taking advantage of the symmetry of the lattice, it is possible to simplify the equation to an 8th-degree equation. This is done by splitting the lattice into two sublattices and decoupling the equations for each sublattice. This is known as the 'decoupling approximation' and is a common method for solving weak potential problems.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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