# Finding entropy change when house leaks heat

1. Dec 18, 2011

### rubenhero

1. The problem statement, all variables and given/known data
b) The temperature inside a house is Tin = 19.2° C when the temperature outside is Tout = 10.7° C. If Q = 5.49 kJ of heat leak from the house to the outside, find the change in entropy caused by this process.

2. Relevant equations
W = QH - QC, dS = dQ/T

3. The attempt at a solution
dS = 5.49kJ/283.7K = .0193514276kJ/K

The answer I calculated was wrong, should I include the entropy inside the house?
Any help is appreciated!

2. Dec 18, 2011

### I like Serena

Hi rubenhero!

Inside you lose ΔS=-Q/TH.
Outside you gain ΔS=Q/TL.

The question in your problem statement is not entirely clear, but I suspect the total change in entropy is intended, which is the sum of both entropy changes.

3. Dec 18, 2011

### rubenhero

Thanks you for responding. You were right, I just did the sum of the entropy loss and gain and got an answer of .5629265733 J/K. Webassign marked my answer as right. Thanks again for your help!

4. Dec 18, 2011

### I like Serena

You're welcome! :)