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Hi, I am trying to solve this problem here:
http://img201.imageshack.us/img201/7006/springqo9.jpg
We're supposed to find the equation of motion from the lagrangian and not Newton's equations.
Attempted solution:
[tex]L = T - U = \frac{I\omega^2}{2} + \frac{mv^2}{2} - \frac{kr^2}{2}[/tex]
[tex]I = m(r^2 + l^2)[/tex]
[tex]v = \frac{dr}{dt}[/tex]
From the euler-lagrange equation [tex]\frac{\partial L}{\partial r} = \frac{d}{dt}\frac{\partial L}{\partial v}[/tex] I get:
[tex]m\omega^2r - kr = m \frac{d^2r}{dt^2}[/tex]
[tex](\omega^2-\frac{k}{m})r = \frac{d^2r}{dt^2}[/tex]
If anyone can see any mistakes i'd appreciate it if they could let me know. Thanks
http://img201.imageshack.us/img201/7006/springqo9.jpg
We're supposed to find the equation of motion from the lagrangian and not Newton's equations.
Attempted solution:
[tex]L = T - U = \frac{I\omega^2}{2} + \frac{mv^2}{2} - \frac{kr^2}{2}[/tex]
[tex]I = m(r^2 + l^2)[/tex]
[tex]v = \frac{dr}{dt}[/tex]
From the euler-lagrange equation [tex]\frac{\partial L}{\partial r} = \frac{d}{dt}\frac{\partial L}{\partial v}[/tex] I get:
[tex]m\omega^2r - kr = m \frac{d^2r}{dt^2}[/tex]
[tex](\omega^2-\frac{k}{m})r = \frac{d^2r}{dt^2}[/tex]
If anyone can see any mistakes i'd appreciate it if they could let me know. Thanks
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