Finding equation of tangent plane & normal line to a given surface

physicsidiot1
Messages
5
Reaction score
0

Homework Statement



Find equations of the tangent plant and the normal line to x-z=4arctan(yz) at (1+∏, 1, 1)

Homework Equations





The Attempt at a Solution


I took the partials and got fx=0 fy=0 fz=(-4y)/((yz)2+1) so for the plane i got -2z-2=0 and for the normal line I got .5z-2=0. I feel like I may have messed up somewhere, probably in taking the partials...
 
physicsidiot1 said:

Homework Statement



Find equations of the tangent plant and the normal line to x-z=4arctan(yz) at (1+∏, 1, 1)

Homework Equations





The Attempt at a Solution


I took the partials and got fx=0 fy=0 fz=(-4y)/((yz)2+1) so for the plane i got -2z-2=0 and for the normal line I got .5z-2=0. I feel like I may have messed up somewhere, probably in taking the partials...

Start by writing your function like this:

f(x,y,z) = x - z - 4arctan(yz) = 0

Then look again at your partials (they are all three wrong). In particular, for example, how do you get fx = 0 out of that, for starters? Show us what you get for your normal vector then we can talk.
 
When I look at x- z= 4 arctan(yz), I see both x and y variables in it. So the derivatives fx and fy can't be 0.

But since you never say exactly what "f" is, it is impossible to tell what you are doing.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
2
Views
2K
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K