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Melvincalvin
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HF(aq) ↔ H+ + F-
Determine equilibirum concentrations with Initital concentrations and Kc.
Kc = 7.2 x 10-4
[HF] = 1.00M
[NaF] = 0.50M
I understand how to do an ICE table and put together questions, but what do you do with [NaF] when it is not part of the chemical equation? How to I factor it into it? Thanks!
Determine equilibirum concentrations with Initital concentrations and Kc.
Kc = 7.2 x 10-4
[HF] = 1.00M
[NaF] = 0.50M
I understand how to do an ICE table and put together questions, but what do you do with [NaF] when it is not part of the chemical equation? How to I factor it into it? Thanks!