Finding F'(x) for Square Root of x

[MattsAli1108]

Homework Statement

F(x)= square root of x

what would F'(x)=?
(F prime of x)

Homework Equations

F(x)= 3x^2
F'(x)=6x

F(x)= x^3
F'(x)=3x^2

The Attempt at a Solution

no clue. If the variable is a square root, it wouldn't have an exponent, right?
confused.

 

[cristo]

Homework Statement

F(x)= square root of x

what would F'(x)=?
(F prime of x)

Homework Equations

F(x)= 3x^2
F'(x)=6x

F(x)= x^3
F'(x)=3x^2

The general equation you're after is \frac{d}{dx}(x^n)=nx^{n-1}

The Attempt at a Solution

no clue. If the variable is a square root, it wouldn't have an exponent, right?
confused.

Have you not come across fractional powers? i.e. the nth root of x is denoted x^1/n?

 

[MattsAli1108]

I have, just failed to make the connection. Calculus is not my strong point. Thank you very much for your help.