A man shoots an arrow 145m/s at 61o from a height of 15m where the ground below is the origin.
A.) Where will the arrow be in 1.5 seconds (X,Y)?
B.) What will be the displacement when the arrow lands in regards to where it was shot from
I believe the kinematic equation Displacement=Vit+(1/2a)t2
as well as Vf=Vi-at
Vi = Initial Velocity
Vf = Final Velocity
a = Acceleration
t = Time
The Attempt at a Solution
I got 105.4m for x and 190 - 1.5(9.83) for y
for my location of where the arrow landed I got (1050m,-15m), because -15 is (0,0) and in regards to where it was shot it is 15m down and 1050=145*12.8+(1/2 -9.83)*12.82
for the Vf I got 19.1m/s because Vf=145-9.83*12.8
Note: I honestly am lost how to solve the problems