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## Homework Statement

A man shoots an arrow 145m/s at 61

^{o}from a height of 15m where the ground below is the origin.

A.) Where will the arrow be in 1.5 seconds (X,Y)?

B.) What will be the displacement when the arrow lands in regards to where it was shot from

## Homework Equations

I believe the kinematic equation Displacement=Vit+(1/2a)t

^{2}

X=ViCosTheta

Y=ViSinTheta

Theta=Tan

^{-1}(Y/X)

as well as Vf=Vi-at

where

Vi = Initial Velocity

Vf = Final Velocity

a = Acceleration

t = Time

## The Attempt at a Solution

I got 105.4m for x and 190 - 1.5(9.83) for y

for my location of where the arrow landed I got (1050m,-15m), because -15 is (0,0) and in regards to where it was shot it is 15m down and 1050=145*12.8+(1/2 -9.83)*12.8

^{2}

for the Vf I got 19.1m/s because Vf=145-9.83*12.8

Note: I honestly am lost how to solve the problems