Finding frequency of a specific mechanical oscillator -- horizontal rod on pivot

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The discussion revolves around calculating the oscillation frequency of a mechanical oscillator consisting of a rod on a cylinder. The user initially calculated a period of around 5 seconds, which is inconsistent with typical clock oscillations of 1-2 seconds. Participants confirm the calculations are correct but suggest revisiting the moment of inertia, particularly considering the rod's length and mass distribution. The conversation also touches on the effects of the rod's width on the moment arm and the resulting oscillation behavior, leading to insights about the conditions under which oscillation occurs. Ultimately, the user expresses gratitude for the assistance and acknowledges the learning gained from the discussion.
  • #31
srecko97 said:
On the other side it gets shorter for b*sinφ
Yes.
 
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  • #32
But when talking about small φ that has no sense
 
  • #33
srecko97 said:
But when talking about small φ that has no sense
Why is that?
 
  • #34
sin φ ≈ 0 for small φ
 
  • #35
srecko97 said:
sin φ ≈ 0 for small φ
That's going too far in the approximation.
 
  • #36
I did the same approximation in the first part of my homework (calculating the oscillating time), when I say cos φ≈1 for small φ
 
  • #37
Keep terms of first order in φ. cosφ ≈ 1 - φ2/2 ≈ 1 to first order. What about sinφ?
 
  • #38
sinφ=φ-(φ^3)/6
 
  • #39
srecko97 said:
sinφ=φ-(φ^3)/6
So, to first order in φ?
 
  • #40
oh it is φ
 
  • #41
srecko97 said:
oh it is φ
That's right.
 
  • #42
Well, I got that M_right - M_left = mg(rφ-bφ) ...M=torque
 
  • #43
image.jpg


The frequency gets smaller, as numerator gets smaller and denominator gets bigger. I hope it is correct! I would like to say you a big THANK YOU TSny! You helped me a lot... I learned a lot from solving this task with your help. I love this forum...
 
  • #44
Your answer looks correct to me. (b ≥ r is interesting to think about.)

Glad I could help.
 
  • #45
ω2 is then negative, so there is no oscillation in real?
 
  • #46
srecko97 said:
ω2 is then negative, so there is no oscillation in real?
Yes, there is no oscillation. Looking back at your post#43, I think you need to add an overall negative sign to the first equation so that it's

##J \ddot{\phi} = - mg(r-b)\phi##.

If ##b > r## then you can see that ##\ddot{\phi} >0## if ##\phi## is given an initial small, positive value. So, the rod rotates away from the equilibrium position when it is released and there is no oscillation. Of course, the differential equation for ##\phi## breaks down as ##\phi## continues to increase since the differential equation was derived under the assumption that ##\phi## is always small.

Another way to investigate the general behavior of the system for various values of b is to derive the potential energy of the system as a function of ##\phi## without making a small angle approximation. Then plots of the potential energy function for various values of b will reveal a lot about the behavior. But that's probably for a rainy day.
 
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