- #36
srecko97
- 82
- 13
I did the same approximation in the first part of my homework (calculating the oscillating time), when I say cos φ≈1 for small φ
So, to first order in φ?sinφ=φ-(φ^3)/6
That's right.oh it is φ
Yes, there is no oscillation. Looking back at your post#43, I think you need to add an overall negative sign to the first equation so that it'sω^{2} is then negative, so there is no oscillation in real?