Finding g(t) with Laplace Transform of G(S)

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SUMMARY

The discussion focuses on finding the time-domain function g(t) from the Laplace transform G(S) = 2/s(e^(-3s)e^(-4s)). The expression is clarified as G(S) = (2S + 1/S^2)e^(-2s)(3s + 1/S^2)e^(-3s). Participants emphasize the importance of proper notation to distinguish between numerators and denominators in rational expressions, specifically addressing the ambiguity in the expression (2S + 1/S^2) and its interpretation.

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goodtime
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G(S)=2/s(e^-3s_e^-4s)

G(S)=(2S+1/S^2)*e^-2s_(3s+1/s^2)*e-3s


find g(t)?
 
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goodtime said:
G(S)=2/s(e^-3s_e^-4s)

G(S)=(2S+1/S^2)*e^-2s_(3s+1/s^2)*e-3s


find g(t)?
First off, what work have you already done?
Second, what operation does '_' represent in e^-3s_e^-4s? If it's multiplication, you can write it as (e^(-3s)*e^(-4s))
Third, without parentheses, it's difficult to tell what's in the numerator of a rational expression, and what's in the denominator. E.g., does (2S + 1/S^2) in your second problem mean
[tex]2S + \frac{1}{S^2}[/tex]
or
[tex]\frac{2S + 1}{S^2}[/tex]?
 

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