# Finding horizontal force using mass and static friction?

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1. Dec 15, 2014

### Infinite324

1. The problem statement, all variables and given/known data
There is a box that has a mass of 30 kg. The coefficient of the static friction is 0.75. Find the horizontal force.

2. Relevant equations
Fs=muFn
F=ma
3. The attempt at a solution
Fs=(.75)(.98)(.30)=.2205 N

That is probably way off... I am very confused right now. Could someone please explain the steps to solving it?

2. Dec 15, 2014

### Staff: Mentor

This can't possibly be the exact problem statement. Please provide the exact problem statement (word for word).

Chet

3. Dec 15, 2014

### Infinite324

The mass of the garbage can is 30 kg. The coefficient of the static friction between the can and the ground is .75.
What is the horizontal force necessary to get the can moving?

4. Dec 15, 2014

### Staff: Mentor

Much better. Now in your post #1, what does the 0.98 represent, and what does the 0.30 represent (including their units)?

Chet

5. Dec 15, 2014

### Infinite324

.98 m/s/s represents gravity and sorry I typed it wrong. It should be 30 N

6. Dec 15, 2014

### Infinite324

30 kg not 30 N

7. Dec 15, 2014

### Staff: Mentor

It should be 9.8 m/s/s. How did the 30 kg become 0.30?

Chet

8. Dec 16, 2014

### Infinite324

Wow yes 9.8 for Gravity. How should I continue then?

9. Dec 16, 2014

### Staff: Mentor

Chet

10. Dec 16, 2014

### Infinite324

Should I multiply (9.8)(30)(.75)?

11. Dec 16, 2014

### Staff: Mentor

If you're not sure about this, you need to go back and review your text and/or notes. The objective of studying a course is so that you can understand the fundamentals (and use this to solve a wide array of problems), rather than just to solve one specific problem.

Chet