# Finding horizontal force using mass and static friction?

## Homework Statement

There is a box that has a mass of 30 kg. The coefficient of the static friction is 0.75. Find the horizontal force.

Fs=muFn
F=ma

## The Attempt at a Solution

Fs=(.75)(.98)(.30)=.2205 N

That is probably way off... I am very confused right now. Could someone please explain the steps to solving it?

Chestermiller
Mentor
This can't possibly be the exact problem statement. Please provide the exact problem statement (word for word).

Chet

The mass of the garbage can is 30 kg. The coefficient of the static friction between the can and the ground is .75.
What is the horizontal force necessary to get the can moving?

Chestermiller
Mentor
The mass of the garbage can is 30 kg. The coefficient of the static friction between the can and the ground is .75.
What is the horizontal force necessary to get the can moving?
Much better. Now in your post #1, what does the 0.98 represent, and what does the 0.30 represent (including their units)?

Chet

.98 m/s/s represents gravity and sorry I typed it wrong. It should be 30 N

30 kg not 30 N

Chestermiller
Mentor
.98 m/s/s represents gravity and sorry I typed it wrong. It should be 30 N
It should be 9.8 m/s/s. How did the 30 kg become 0.30?

Chet

Wow yes 9.8 for Gravity. How should I continue then?

Chestermiller
Mentor
Wow yes 9.8 for Gravity. How should I continue then?

Chet

• Bystander
Should I multiply (9.8)(30)(.75)?

Chestermiller
Mentor
Should I multiply (9.8)(30)(.75)?
If you're not sure about this, you need to go back and review your text and/or notes. The objective of studying a course is so that you can understand the fundamentals (and use this to solve a wide array of problems), rather than just to solve one specific problem.

Chet