Finding initial velocity and theta, given range and height

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SUMMARY

The discussion focuses on calculating the initial velocity (V_o) and launch angle (theta) of a stone thrown down a slope, given a range (R) of 50 meters and a maximum height (h) of 12 meters. The user attempts to decompose the velocity into horizontal (V_xo) and vertical (V_yo) components using trigonometric functions, specifically V_xo = vcos(theta) and V_yo = vsin(theta). The user struggles with determining time (t) and seeks an equation that does not involve time, ultimately considering the equation v_y^2 = V_yo^2 - g(y - yo) for further analysis.

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Homework Statement



A stone is thrown down a slope. I am given the Range of the slope and the max height from spot thrown.
R= 50m
h= 12m

Homework Equations



I need to determine the magnitude of Vo and inital theta.

The Attempt at a Solution



First I need to find V_o:
I feel that the only relevant portion to find the initial velocity is from the spot thrown to the max height where V_yo is 0. I broke up the components of velocity so that:
V_xo=vcos(theta)
V_yo=vsin(theta)

However, I'm lost after this because I don't know t. My first idea was to find t, but I was having problems finding an equation that doesn't use v, theta, in a time equation.
My second idea was to find an equation that avoids time such as v_y^2=V_yo^2-g(y-yo).

I haven't attempted the initial theta part yet.
 
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Reading through this post, this morning, I realized I forgot to add that the slope has a rise of 30m and a run of 40m. I don't feel that would help with find V_o though. :/
 

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