Finding Initial Velocity with Given Distance and Angle?

Click For Summary
SUMMARY

The problem involves calculating the initial velocity required for a ball launched from a 28-meter high cliff at an angle of 31° to hit a target 65 meters away. The discussion highlights the use of kinematic equations, specifically V_x = V_{x0} + a_x*t and x = x_0 + v_{x0}*t + (1/2)a_x*t^2. The user attempts to decompose the initial velocity into horizontal and vertical components but struggles with the lack of information regarding time and final velocity components. The conversation suggests utilizing v-t diagrams and geometry as alternative methods to solve the problem.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of vector decomposition of velocity
  • Familiarity with projectile motion concepts
  • Ability to analyze v-t diagrams and geometric relationships
NEXT STEPS
  • Study the derivation and application of kinematic equations in projectile motion
  • Learn about vector decomposition techniques for initial velocity
  • Explore the use of v-t diagrams in solving motion problems
  • Investigate the effects of air resistance on projectile motion
USEFUL FOR

Students in physics, particularly those studying projectile motion, educators looking for problem-solving strategies, and anyone interested in applying kinematic equations to real-world scenarios.

vaironl
Messages
34
Reaction score
0
Hello, All!

The following problem wasn't assigned to me, it was used for last semesters physics class at my college. However, I feel it is interesting enough and I can't seem to find the correct answer.

A ball is launched from the top of a 28-m high vertical cliff at an angle of 31° . Ignoring the effects of air resistance, if the ball is to hit a target on the ground a horizontal distance 65-m away from the edge of the cliff, with what initial speed must it be launched?

This is the problem and I haven't excluded or included information.

Homework Equations


[/B]
V_x= V_{x0} + a_x*t
x = x_0 + v_{x0}*t + (1/2)a_x*t^2
x - x_0 = t * (v_{x0} + v_x)/(2)

a_y = m*g

The Attempt at a Solution


[/B]
I first attempted to split the initial velocity to its components
V_{x0} = cos(31) * V, Vy_{y0} = sin(31)*V

I assumed there's no acceleration in the horizontal direction and noticed that Vx = V_(x0)

Now I feel like I don't have enough given information to get the initial velocity since all kinematic equations given depend on initial velocity components which is not given. Neither are we given final velocity components.

At some point I noticed x - x_0 = t * \frac{v_{x0}+ vx}{2} can be manipulated in the following way

v_x = v_{x0}
x-0 =\frac{v_{x0}+v_{x0}}{2}t
x=\frac{2v_{x0}}{2}t
v_{x0} = \frac{x}{t}

x = 65, but t seems more difficult to find.

Am I even heading somewhere here?
 
Physics news on Phys.org
Now I feel like I don't have enough given information to get the initial velocity since all kinematic equations given depend on initial velocity components which is not given. Neither are we given final velocity components.
... You have 4 equations and 4 unknowns.
What's the problem?

List the equations, list the values you know. Just like normal.

The other approach is to sketch out the v-t diagrams and just use geometry.
You know how to find slopes of lines and the areas of simple polygons.
 
Last edited:
Simon Bridge said:
... You have 4 equations and 4 unknowns.
What's the problem?

List the equations, list the values you know. Just like normal.

The other approach is to sketch out the v-t diagrams and just use geometry.
You know how to find slopes of lines and the areas of simple polygons.

Thank you again Mr. Bridge!
I have some university activity early tomorrow. I will attempt this problem and post my attempt.
 

Similar threads

Replies
4
Views
1K
Replies
62
Views
7K
Replies
10
Views
2K
Replies
13
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
11
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
4K
Replies
11
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K