Finding Internal Forces With Joints & Sections

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SUMMARY

The discussion centers on the application of both the method of joints and the method of sections in structural analysis of trusses. The user successfully calculated internal forces using both methods, specifically finding Ly=52.5, Ry=32.5, Fhg=54.17 C, Fhj=43.34 T, Fjg=0, Feg=54.17 C, Fkg=0, Fek=25 T, and Fwk=43.34 T. It is confirmed that both methods can be utilized simultaneously, as the method of joints is essentially a specific application of the method of sections at individual joints. This flexibility allows for a comprehensive analysis of internal forces within truss structures.

PREREQUISITES
  • Understanding of truss structures and their components
  • Proficiency in the method of joints for analyzing forces
  • Proficiency in the method of sections for analyzing forces
  • Knowledge of equilibrium equations in static systems
NEXT STEPS
  • Study the application of the method of joints in complex truss systems
  • Explore the method of sections for determining internal forces in larger structures
  • Learn about the relationship between the method of joints and method of sections
  • Investigate software tools for structural analysis, such as SAP2000 or ANSYS
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in truss design and analysis will benefit from this discussion, particularly those looking to deepen their understanding of internal force calculations in trusses.

jhox08
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I have the truss shown, I'm supposed to find the internal force for each of the vertical members...I understand method of joints and method of sections, but can you use both method of joints and sections in the same problem...for example I found Ly=52.5 and Ry=32.5 using moments and summing in the Y direction, next I used method of joints at H to find Fhg=54.17 C and Fhj=43.34 T, then I used method of joints again at J to find Fjg = 0, but then I made a cut just to the left of G and J exposing Feg, Fgk and Fjk, I found Feg=54.17 C and Fkg=0 by method of sections but used method of joints at K to find Fek=25 T and Fwk=43.34 T, so my question is can I solve this problem using both methods at the same time?...thanks
 

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Yes, I think you can use both methods in the same problem.
 
They are really the same thing. The method of joints IS the method of sections applied to a single joint. The section cut does not have to be a straight line.
 

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