Finding kernel of matrix transformation

Click For Summary
SUMMARY

The discussion focuses on finding the kernel of the matrix transformation defined by the equation f(x) = Ax, where the matrix A is given as:
A =
1 -1 0
0 1 -2. The kernel is determined by solving the homogeneous system of equations derived from Ax = 0, resulting in the equations X1 - X2 = 0 and X2 - 2X3 = 0. The solution involves reducing the system to its reduced row echelon form and expressing the variables X1, X2, and X3 in terms of a free parameter, specifically choosing X3 = t.

PREREQUISITES
  • Understanding of matrix transformations
  • Knowledge of homogeneous linear equations
  • Familiarity with reduced row echelon form (RREF)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn about matrix transformations and their properties
  • Study methods for solving homogeneous linear equations
  • Explore techniques for converting matrices to reduced row echelon form
  • Investigate the concept of free parameters in linear algebra
USEFUL FOR

Students studying linear algebra, particularly those focusing on matrix transformations and kernel calculations, as well as educators looking for examples of solving systems of linear equations.

DWill
Messages
68
Reaction score
0

Homework Statement


Find the kernel of the matrix transformation given by f(x) = Ax, where

A =
1 -1 0
0 1 -2

(it's a matrix)

Homework Equations


Kernel is the set x in R^n for f(x) = Ax = 0

The Attempt at a Solution


I set up the problem like this:

[
X1
X2 * A = 0
X3
]

Just multiplying the matrices I get:

X1 - X2 = 0
X2 - 2X3 = 0

I think I'm missing something really simple but I'm stuck on what to do now in solving the system of equations for X1, X2, X3. Any hints, suggestions, or corrections? thanks
 
Physics news on Phys.org
You have that system of homogenous linear equations. Now represent in a form of a matrix and reduce it to its reduced row echelon form. Then you can read off the values of x1,x2,x3. Denote variables by parameters if you have to.
 
You have two equations and three unknowns, so you are going to have at least one free parameter, you may as well pick X3=t for your parameter and solve for X1 and X2 in terms of t.
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
3
Views
2K