Finding Laurent Series for a Rational Function on an Annulus

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SUMMARY

The discussion focuses on finding the Laurent series for the rational function f(z) = 1/(z(z-1)(z-2)) within the annulus defined by 1 < |z| < 2. The solution involves performing a partial fraction decomposition resulting in f(z) = 1/2z - 1/(z-1) + 1/(2(z-2)). To derive the Laurent series, the user must expand the first two terms around their singularities using series in 1/z, while the third term should be expressed as a Taylor series in z. This approach effectively addresses the challenge of singularities located inside and outside the annulus.

PREREQUISITES
  • Understanding of Laurent series and their applications.
  • Familiarity with partial fraction decomposition techniques.
  • Knowledge of Taylor series expansion methods.
  • Concept of annuli in complex analysis.
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  • Study the process of deriving Laurent series for functions with multiple singularities.
  • Learn about the properties of annuli in complex analysis.
  • Explore advanced techniques in partial fraction decomposition for complex functions.
  • Investigate the convergence of series expansions in complex analysis.
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Homework Statement


find the Laurent series for f(z) = 1/(z(z-1)(z-2)) on the annulus between 1 and 2. with the origin as center.


Homework Equations





The Attempt at a Solution


so i found the partial fraction decomposition of this function and it turns out to be f(z) = 1/2z + -1/(z-1) + 1/(2(z-2)). In order to find the Laurent series do I just Taylor expand each of my 3 different decomposition around their singularities? However, their singularities are not contained on the annulus so this doesn't seem to make much sense. I am unsure how to proceed from this spot.
 
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Note that 1/2z and -1/(z-1) have their singularity "inside" the annulus, while 1/(2(z-2)) has a singularity "outside" the annulus. Try expressing the first two as series in 1/z and the third one as a series in z (i.e. Taylor series).
 

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