Finding Length and Diameter Of A Wire

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SUMMARY

The discussion focuses on calculating the length and diameter of a copper wire fabricated from 2.00 g of copper with a specified resistance of R = 0.480 Ω. The resistance formula used is R = ρL/A, where ρ represents resistivity, L is the length, and A is the cross-sectional area. The mass of the wire is expressed as M = A * l * d, where d is the density of copper. This relationship is crucial for determining the wire's dimensions based on the given mass and resistance.

PREREQUISITES
  • Understanding of electrical resistance and the formula R = ρL/A
  • Knowledge of material properties, specifically the density of copper
  • Familiarity with basic algebra and geometry for calculating area and volume
  • Concept of uniform wire fabrication and its implications in electrical engineering
NEXT STEPS
  • Research the resistivity values of various materials, including copper
  • Learn how to calculate the cross-sectional area of different wire shapes
  • Explore the relationship between mass, volume, and density in material science
  • Investigate practical applications of wire resistance in electrical circuits
USEFUL FOR

Students studying physics or electrical engineering, particularly those focusing on material properties and electrical resistance calculations.

Bashyboy
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Homework Statement


Suppose you wish to fabricate a uniform wire from 2.00 g of copper. The wire is to have a resistance of* R = 0.480 Ω*and all the copper is to be used.


Homework Equations





The Attempt at a Solution



In the problem, they suggest using this relationship for resistance R=\rho A l. How did they get that? From my understanding, resistance is R = \rho \frac{l}{A}
 
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You are right, R=ρL/A.

ehild
 
The mass is M=Ald, where d is the density.
 

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