Finding Lorentz Vector? -Physics Noob

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The discussion revolves around calculating the Lorentz vector for a collision resulting in two muons, focusing on the components of momentum. The user has successfully determined the transverse momentum (Pt) and its components (Px and Py) using the formulas Px = Pt cos(phi) and Py = Pt sin(phi). The challenge lies in finding the z component of momentum (Pz) and understanding pseudorapidity (η), which relates to the angle from the z-axis. It's clarified that Pt does not include any z component, and the relationship between pseudorapidity and the total momentum is emphasized, allowing the user to derive Pz indirectly. The conversation highlights the importance of correctly interpreting pseudorapidity in the context of momentum calculations.
godtripp
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I was given this as an extra-curricular activity... way over my understanding of physics, sophmore year undergraduate.

But I can use a bit of help.
I'm given data from a collision resulting in 2 muons.

(this is exactly how the text is written to me, if any of these definitions are not exactly correct please note)

For a muon, we measure
"pt", Transverse momentum = sqrt (px^2 + py^2)
"phi", angle in the x-y plane
"eta", pseudorapidity, which is another form of the angle from the z-axis
"mass", the mass of the muon

I need to find the Lorentz vector.

For the energy I figured out
E = sqrt ( mass^2 + momentum^2) where momentum should be the magnitude of the 3vector momentum.

What I'm having trouble with is finding Pz, momentum in the z axis.
Maybe I'm not quite understanding the definition of pseudorapidity?

I'd find Px and Py by
Px=Pt cos(phi) and Py = Pt sin(phi)

But how do I find the z component of momentum?

psuedorapidity only gives me an angle for the z component correct? and am I correct that Ptransverse doesn't contain any z component?
 
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Hi godtripp! :smile:

(have a phi: φ and an eta: η and try using the X2 and X2 icons just above the Reply box :wink:)
godtripp said:
But how do I find the z component of momentum?

psuedorapidity only gives me an angle for the z component correct? and am I correct that Ptransverse doesn't contain any z component?


Yes, Pt is the component transverse to the z-direction, so it's only made up of Px and Py.

Pt = P.sinθ, where θ is the angle from the z-axis.

So you can get P (you don't need Pz) from Pt and η by using η = -logtan(θ/2) … see http://en.wikipedia.org/wiki/Pseudorapidity. :wink:
 
Thank you so much tim. I was thinking of the angle from psuedorapidity in terms of the Pz vector component and not of the total momentum! Thanks!
 

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