Finding Lower Sums for a Region

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SUMMARY

The discussion focuses on calculating the lower sum for the region bounded by the function f(x) = 25 - x² and the x-axis between x = 0 and x = 5. The user attempts to find the left endpoints using the formula mi = 5(i-1)/n and explores sigma notation to derive the final expression for the lower sum. The resulting formula is 125/n³ {(n(n+1)(2n+1)/6) - 2[n(n+1)/2] + n}, indicating a thorough analytical approach to the problem.

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  • Understanding of Riemann sums
  • Familiarity with sigma notation
  • Knowledge of polynomial functions
  • Basic calculus concepts, particularly integration
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Students studying calculus, particularly those focusing on integration and Riemann sums, as well as educators looking for examples of analytical problem-solving in mathematics.

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Homework Statement



FIND THE LOWER SUM FOR THE REGION BOUNDED BY f(x) = 25 - x^2 AND THE X - AXIS BETWEEN x = 0 and x = 5. SOLVE ANALYTICALLY!

Homework Equations



None that I'm aware of...

The Attempt at a Solution



f(x) = -x2 + 25
and
[tex]\Delta[/tex]X = b-a/n = 5-0/n = 5/n



Here's my question: how do I find the left endpoints in order to solve for the lower sum?
 
Last edited:
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Okay, here's what I have thus far, and I'm not sure this is correct:


mi= 5(i-1)/n

After much sigma notation and algebra...

eventually ending up with 125/n3 {(n(n+1)(2n+1)/6) - 2[n(n+1)/2] + n}
 

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