Finding Magnetic Field of Alpha Particle in a Circle

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Homework Help Overview

The discussion revolves around calculating the magnetic field experienced by an alpha particle moving in a circular path perpendicular to a uniform magnetic field. The problem specifies that the particle completes a revolution every 60 nanoseconds and operates under non-relativistic conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between centripetal force and magnetic force acting on the alpha particle. There are questions about the necessity of the radius of the circular path and the forces involved in the motion.

Discussion Status

Some participants have provided insights into the forces acting on the alpha particle and have derived relationships between angular velocity and the magnetic field. There is acknowledgment of a potential error in the original poster's calculations, but no consensus on the exact nature of the issue has been reached.

Contextual Notes

The radius of the circular path is not provided, and there is some debate about its relevance to the problem. The original poster mentions a possible typo in the thread title, indicating a potential source of confusion.

howt
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Homework Statement



An alpha particle is moving at constant speed in a circle, perpendicular to a uniform magnetic field, making a revolution every 60 nanoseconds.
Its speed is non-relativistic

What is the numerical magnitude of the magnetic field in T ?


Homework Equations


alpha particle (2 protons + 2 neutrons)

We have here T= 2(pi)m / qB

in which
m=Mass (alpha particle= 6.64*10^-27) kg
q=Charge = 2(1.6*10^-19) C
T= (60*10^-9) s

The Attempt at a Solution



This should be just plugging in, I got 2.1729, yet it is wrong...
Why?
 
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What is the radius of the circle?
 
it is not given...

I don't think we need it to solve the question
The formula of it doesn't involve any radius...
 
howt said:
it is not given...

I don't think we need it to solve the question
The formula of it doesn't involve any radius...
When the alpha particle is moving ina circle, what is the force acting on it?
What is the force on alpha particle due to the magnetic field?
 
The Centripetal force is going to equal the magnetic force.

Note that w = v/r

Centripetal force , F=m v^2 /r..
=m r w^2

And the magnetic force on the alpha particle is, F = B q v
= B q w r

m r w^2 = B q w r
m w = B q

in which w= 2(pi) / T

Thus T= 2(pi)m / qB
 
Your answer appears to be correct.
 
Thanks, the problem might be those constant...

Side Note: I just realize I got a typo on the topic... crap
 

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