Finding magnitude and direction of an electric field

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SUMMARY

The electric field above a plane of charged particles with charge per unit area σ has a magnitude of σ/∈0 and is directed perpendicular to the plane. This conclusion is derived from applying Gauss's Law, where the electric field E is calculated using the formula E = σ/∈0. The orientation of the electric field is independent of the spaceship's position relative to the plane, focusing solely on the relationship between the field and the plane's surface.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and charge distributions
  • Knowledge of electric flux concepts
  • Basic proficiency in calculus for physics applications
NEXT STEPS
  • Study the application of Gauss's Law in various geometries
  • Learn about electric field lines and their representation
  • Explore the concept of electric flux in different scenarios
  • Investigate the effects of multiple charged planes on electric fields
USEFUL FOR

Students of physics, particularly those studying electromagnetism, educators teaching electric field concepts, and anyone preparing for exams involving electric fields and Gauss's Law.

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Homework Statement


A spaceship encounters a single plane of charged particles, with the charge per unit area equal to σ. The electric field a short distance above the plane has magnitude _____ and is directed _____ to the plane.

a) σ/2∈0, parallel

b) σ/2∈0, perpendicular

c) σ/∈0, parallel

d) σ/∈0, perpendicular

e) 2σ/∈0, parallel

Homework Equations


E = k * (q/r2)

Electric flux = EAcos(φ)

Electric flux = qenclosed / ∈0

The Attempt at a Solution


I'm given σ = q/A

then q = σA

So i plug this into the electric field equation:

E = kσA/r2

substitute k = 1/4π∈0

E = σA/4πr20

I can make a gaussian surface as a sphere, who's surface area is 4πr2 and then substitute that in for A,

then E = σ/∈0

Now I'm not sure how to find the direction and also I'm unsure how to think about this problem. Is the plane under the spaceship or directly in front of it, and what orientation is it at? Am i supposed to find this?
 
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fishturtle1 said:
make a gaussian surface as a sphere,
A short fat cylinder (pillbox) would be more usual here, but the result is the same.
You do need to think about whether all of the flux coming out of it is directed towards the spacecraft , though.
fishturtle1 said:
Is the plane under the spaceship or directly in front of it,
It doesn't matter. The question asks for the orientation of the field in relation to that of the plane (not "spaceplane").
 

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