Finding magnitude direction and speed of a plane trip

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SUMMARY

The discussion focuses on calculating the magnitude and direction of a plane's displacement and average velocity during a trip from city A to city C. The plane travels 425 km east and 954 km south, resulting in a total displacement magnitude of 1044.39 km and a direction of -65.987 degrees. The average velocity calculations initially yielded incorrect results due to the use of average velocities over different time intervals. The correct approach involves defining velocity in terms of total displacement rather than segmental velocities.

PREREQUISITES
  • Understanding of vector addition and displacement
  • Knowledge of trigonometric functions, specifically tangent and inverse tangent
  • Familiarity with average speed and average velocity concepts
  • Basic proficiency in unit conversions, particularly time from minutes to hours
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  • Study the relationship between average velocity and displacement
  • Learn about the use of trigonometric functions in physics problems
  • Practice problems involving average speed and average velocity calculations
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wbetting
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Homework Statement


A plane flies 425 km east from city A to city B in 40.0 min and then 954 km south from city B to city C in 1.70 h. For the total trip, what are the (a) magnitude (in km) and (b) direction of the plane's displacement, the (c) magnitude (in km/h) and (d) direction of its average velocity, and (e) its average speed (in km/h)? Give your angles as positive or negative values of magnitude less than 180 degrees, measured from the +x direction (east).


Homework Equations



magnitude is sqrt of a^2+b^2
direction is tan inverse of ay/ax

The Attempt at a Solution


ok so i found magnitude and direction and got parts a and b, c,e right but got part d, wrong and i think its because of a mathematical mistake but its driving me nuts! i got 1044.39 km for a and -65.987 degrees for b. for c i found velocity avg for x and y for avg velocity of x i did (425km/.666hr)= 637.5 km/h
for avg velocity y i did (954km/1.7 hr)= 384.71 km/hr
for d i did sqrt 637^2+384.71^2= 434.33 km/hr
i can't figure out what i did wrong on d i did inverse tan of -434.33/637.5 and keep getting -34.26 and at one point got -31.11. whattt am i doing wrong?!
 
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Hi wbetting! :biggrin:

For part (d) you found the tan for the average velocities over different time intervals. That's why you get the wrong answer. But what is the actual direction of velocity? (Hint:defining velocity in terms of displacement will help)
 

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