Finding mass of an object on a spring, given Frequency

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SUMMARY

The discussion centers on calculating the mass of an object on a spring given its oscillation frequencies of 0.84 Hz and 0.65 Hz when an additional 730 g mass is added. The participant utilized the formula m = k/(2πf)² to derive the mass but initially arrived at incorrect results. After multiple attempts, the participant successfully calculated the correct mass, indicating the importance of careful equation manipulation and verification in physics problems.

PREREQUISITES
  • Understanding of harmonic motion and oscillation principles
  • Familiarity with the spring constant (k) and its role in oscillatory systems
  • Knowledge of the relationship between frequency (f) and angular frequency (ω)
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Review the derivation of the mass-spring system equations
  • Explore the effects of mass changes on oscillation frequency in spring systems
  • Learn about the concept of damping in oscillatory motion
  • Investigate the relationship between spring constant (k) and mass in different materials
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to mass and frequency in spring systems.

Zach_Sch
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Homework Statement


A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .

Homework Equations


f*2pi = w
w = (k/m)^1/2
f = (1/2pi)*(k/m)^1/2

The Attempt at a Solution


I simply used the third equation twice, rearranging to the following:
m = k/(2pi*f)^2
using this equation two different times I ended up with:
m = k / (2pi*.84)^2
m + .73 = k / (2pi*.65)^2
I solved the above equations for m and came out with the wrong answer.

Any help is greatly appreciated! Thanks in advance : )
 
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Zach_Sch said:

Homework Statement


A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .

Homework Equations


f*2pi = w
w = (k/m)^1/2
f = (1/2pi)*(k/m)^1/2

The Attempt at a Solution


I simply used the third equation twice, rearranging to the following:
m = k/(2pi*f)^2
using this equation two different times I ended up with:
m = k / (2pi*.84)^2
m + .73 = k / (2pi*.65)^2
I solved the above equations for m and came out with the wrong answer.

Any help is greatly appreciated! Thanks in advance : )
Can you show your math at the end where you solve the two equations for m? That may help us spot any errors... :smile:
 
berkeman said:
Can you show your math at the end where you solve the two equations for m? That may help us spot any errors... :smile:
Haha, so I attempted to solve my systems of equations three different times and got a very large negative mass, I just attempted it again and got the correct answer.
Sorry about that ... cheers
 
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