A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .
f*2pi = w
w = (k/m)^1/2
f = (1/2pi)*(k/m)^1/2
The Attempt at a Solution
I simply used the third equation twice, rearranging to the following:
m = k/(2pi*f)^2
using this equation two different times I ended up with:
m = k / (2pi*.84)^2
m + .73 = k / (2pi*.65)^2
I solved the above equations for m and came out with the wrong answer.
Any help is greatly appreciated! Thanks in advance : )