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## Homework Statement

A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .

## Homework Equations

f*2pi = w

w = (k/m)^1/2

f = (1/2pi)*(k/m)^1/2

## The Attempt at a Solution

I simply used the third equation twice, rearranging to the following:

m = k/(2pi*f)^2

using this equation two different times I ended up with:

m = k / (2pi*.84)^2

m + .73 = k / (2pi*.65)^2

I solved the above equations for m and came out with the wrong answer.

Any help is greatly appreciated! Thanks in advance : )