Finding mass of charged particle - magnetic field

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The discussion revolves around calculating the mass ratio of two charged particles entering a magnetic field with the same kinetic energy. The radius of the circular path for the heavier particle is 1.1 times that of the lighter particle, leading to the need for a relationship between mass and radius in a magnetic field. Key equations include the kinetic energy and the radius formula, which relate mass, charge, and magnetic field strength. The conversation highlights the importance of momentum and kinetic energy in determining the mass ratio, emphasizing that the heavier particle will have a larger radius due to its greater mass. The participants are encouraged to derive the mass ratio using the established relationships between momentum and kinetic energy.
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Homework Statement



an isotope separator is used to separate charged particles having different masses. assume that two types of particles enter a region of constant magnetic field with the same kinetic energy, and assume that all particles have the same charge.

the radius of the circular path followed by the heavier particles is found to be 1.1 times that for the lighter particles. what is the ratio of their masses?


Homework Equations



kinetic energy U = 1/2(CV^2) = KE = 1/2(mv^2) where C is capacitance, V is electric potential, m is mass, v is velocity

radius r = mv/qB where q is charge, B is magnetic field

The Attempt at a Solution



i set up two relationships using both equations for each particle, the lighter and the heavier.

lighter particle:

r = mv/qB = ---> v = rqB/m ---> KE = 1/2(mv^2) = 1/2(m(rqB/m)^2) = (rqB)^2/2m

heavier particle:

i want to use the r = mv/qB but since both particles have same kinetic energy, the mass will be greater but the velocity will be lower than that of the lighter particle.

what would be the best way to determine the mass and velocity of the heavier particle? should i assume an arbitrary amount, say two times greater?

is my approach for the lighter particle along the right lines, or is there a better way?
 
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First answer me this:

An electron and a proton are injected into a uniform magnetic field at right angles to the direction of the field with the same Kinetic Energy. Then:
a)the electron trajectory will be less curved than the proton trajectory
b)the proton trajectory will be less curved than the electron trajectory
c)both the trajectories will be equally curved
d)both the trajectories will be straight.

Once you get this, go ahead.


The angular frequency of a charged particle in a uniform magnetic field is independent of its velocity or energy.This is also known as cyclotron theory.
Heavier the particle is , larger is its radius ; faster a particle is , larger is the radius.

Where does the confusion lie?

You are on the right track.Go ahead.
 
Last edited:
Can you find the relation between momentum and kinetic energy?
 
physixguru:

"b)the proton trajectory will be less curved than the electron trajectory" - because proton has greater mass than electron thus less affected by magnetic field

a little confused about how the problem is stated, i can't really assume the two particles are either both electrons or both protons because one is heavier, yet they share the same charge.

rl.bhat:

momentum p = mv
kinetic energy KE = 1/2(mv^2)
so KE = 1/2(p^2) ??
 
so KE = 1/2(p^2) ??
This is wrong.
KE = 1/2(p^2)/m or p = (2mE)^1/2...(1)
radius r = mv/qB where q is charge, B is magnetic field
This can be written as p = qBr...(2)
Compare eq. 1 and 2 and find the ratio of the masses. Note that the KE is same for both the masses.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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