Finding mass of fat on a chicken by volume and density

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SUMMARY

The discussion focuses on calculating the mass of fat in a chicken using principles of buoyancy and density. The mass of the chicken in air is 1.489 kg, while its mass in water is 0.112 kg, leading to a displaced water mass of 1.377 kg and a corresponding volume of 1.377E-3 m³. The equations used include the relationships between mass, volume, and density for fat (900 kg/m³) and the rest of the chicken (assumed to be 1100 kg/m³). Tim successfully derived the mass of fat using substitution methods in his calculations.

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Homework Statement


This was a lab we did in class 2 day we took the measured the weight of a chicken in the air and in water. Than found the masses and mass of h20 displaced and the volume displaced

Mass chicken in air = 1.489 kg
Mass chicken in h20 = .112 kg

Mass h20 displaced = 1.377 kg
Volume h20 displaced = 1.377E –3 m3




Homework Equations


1. Mass fat + Mass rest of chicken (else) = 1.489 kg
2. Volume fat + V else = 1.377E –3 m3
3. density Fat = 900 kg/m3 = Mass fat/ V fat
4. density else = 100 kg/m3 = Mass else/V else



The Attempt at a Solution



So I assume this is a substitution prob. I need to sub. V fat= Mass fat/ 900kg/m3
into one of the equations.

So what I did so far was

Mass fat /900kg/m3 + Mass else/1100kg/m3 = 1.377E –3 m3

Mass fat/ 900kg/m3= 1.377E –3 m3 – Mass else/1100kg/m3

Mass fat= 900kg/m3(1.377E –3 m3 – Mass else/1100kg/m3)

Mass fat= 1.2393kg – 99E4 Mass else is this wrong so far?

Any help would be great we just did the lab today and its due Friday and I need the calcs done to do the report, thanks
-Tim
 
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