Finding max/min of 3d graphs with chain rule

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SUMMARY

The discussion focuses on solving problem number 2 from a practice midterm that involves finding the maximum and minimum values of a 3D graph using the chain rule. Participants clarify that the chain rule is not necessary for this problem; instead, substituting x and y in z(x,y) with their expressions in terms of t and differentiating with respect to t is the correct approach. The problem contains two critical points, one representing a minimum and the other a maximum, despite initial confusion regarding the presence of a saddle point.

PREREQUISITES
  • Understanding of multivariable calculus
  • Familiarity with the chain rule in calculus
  • Knowledge of critical points in functions
  • Ability to differentiate functions with respect to a variable
NEXT STEPS
  • Study the method of substituting variables in multivariable functions
  • Learn how to identify and classify critical points in 3D graphs
  • Practice differentiating functions with respect to a parameter
  • Explore applications of the chain rule in multivariable calculus
USEFUL FOR

Students and educators in multivariable calculus, particularly those tackling optimization problems involving 3D graphs and critical point analysis.

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http://math.berkeley.edu/~theojf/Midterm2Practice.pdf

can someone please help me on problem number 2 of the link above?
apologies for the bad handwriting. my professor is just horrible with that.

i've done max and min with multivariables before and I've done chain rule , but I've never combined the two. also, in that problem, the only critical point seems to be a saddle point, so I'm not sure what the "lowest" point is referring to
 
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You don't need to use the chain rule- in fact you don't need to worry about multi-variables at all. Replace x and y in z(x,y) with their expressions in terms of t and differentiate with respect to t. There are two critical points. One is a minimum and the other a maximum.
 

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