Finding Max & Min of r=2-2cos(\Theta)

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SUMMARY

The discussion centers on finding the maximum and minimum values of the polar equation r = 2 - 2cos(Θ). The maximum value is determined to be 4 at Θ = π, while the minimum value is 0 at Θ = 0 and Θ = 2π. A key point raised is the distinction between equations and functions, emphasizing that only functions possess maximum or minimum values.

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  • Understanding of polar coordinates and equations
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  • Familiarity with the concepts of maxima and minima in calculus
  • Ability to interpret polar equations graphically
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Students studying calculus, particularly those focusing on polar coordinates, as well as educators teaching mathematical concepts related to maxima and minima.

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Homework Statement


Find the Maximum and Minimum of the following equation.
r=2-2cos([tex]\Theta[/tex])


The Attempt at a Solution


Max- 2-2 cos (0[tex]\pi[/tex])=0
(0,0[tex]\pi[/tex]);(0,2[tex]\pi[/tex])

Min 2-2cos([tex]\pi[/tex])=4
(4,[tex]\pi[/tex])

Do i just have these backwards?
 
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0<4, so yes, you have them backwards. 4 is the max, 0 is the min.
 
I'm wondering how you determined that
Max- 2-2 cos (0)=0
(0,0[itex]\pi[/itex\);(0,2[itex]\pi[/itex])<br /> <br /> Min 2-2cos()=4<br /> (4,[itex]\pi[/itex])[/itex]
[itex] <br /> And, by the way, an <i>equation</i> does <b>not</b> have a max or min- a <i>function</i> does. An equation does not even have a "value" to be max or min.[/itex]
 

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