Finding maximum curvature on lnx

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    Curvature Maximum
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Homework Help Overview

The discussion revolves around finding the point on the curve defined by the function f(x) = ln x where the curvature is maximized. Participants are exploring the mathematical concepts related to curvature and its calculation.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the curvature formula and express it in terms of derivatives of the function. There are questions about the correctness of the derivatives and the application of the quotient rule for finding local maxima. Some participants express confusion about the notation used in the equations.

Discussion Status

There is ongoing exploration of the curvature formula and its components. Some participants have provided feedback on potential errors in the expressions, while others are questioning the complexity of the problem and how to approach differentiation. The discussion is active, with participants clarifying terms and seeking to simplify the problem.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is also uncertainty regarding the correctness of the initial setup and the implications of the derived formulas.

tensor0910
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Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = || T ' (x) || / || r ' (x ) ||

k (x) = f '' (x) / [ 1 + ( f '' (x))2 ] 3/2[/B]

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = -1/x2

k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
 
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tensor0910 said:

Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = ιι T ' (x) ιι / ιι r ' (x ) [/B]
There's a lot of extra stuff that I can't read in your formula above. What are these characters? ιι
tensor0910 said:

k (x) = ι f '' (x) ι / [ 1 + ( f '' (x))2 ] 3/2
And what's this one? ι
tensor0910 said:

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = 1/x2
You lost a sign here (above).
tensor0910 said:
k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
Sure, quotient rule would work, provided you are careful and methodical. It would be helpful to simplify the expression as much as possible for attempting to differentiate it.
 
I cleaned it up a bit. Sorry!
 
tensor0910 said:

Homework Statement



Determine the point on a plane curve f(x) = ln x where the curvature is maximum.[/B]

Homework Equations



k(x) = || T ' (x) || / || r ' (x ) ||

k (x) = f '' (x) / [ 1 + ( f '' (x))2 ] 3/2[/B]

The Attempt at a Solution



f ' (x) = 1/x
f " (x) = -1/x2

k(x) = 1/x2 / { [1 + (1/x)2 ] 3/2 }

k(x) = 1/x2 / { [ x2 +1 /x2 ] 3/2 }

iirc we can use the first derivative and try to find the local max...but how do we even start it with this mess? quotient rule? Maybe there's something about the problem that tells us its impossible...? I'm lost here...
There are some mistakes in your formulas.
 

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