Finding Net Force on a 725 Gram Block with Given Acceleration and Angle

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To find the net force on a 725-gram block accelerating at 8.10 m/s² at an 18-degree angle, first convert the mass to kilograms. Use Newton's second law, F = m*a, to determine the force components in the x and y directions. Calculate the x and y components of acceleration using trigonometry, which involves drawing a triangle to resolve the angle. Once you have F_x and F_y, the magnitude of the net force can be found using the formula √(F_x² + F_y²). The angle does not complicate the calculation; it simply requires breaking the acceleration into components.
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Homework Statement


Find the magnitude of net force on the following object a 725 gram block that is accelerating at 8.10 m/s2 at an angle of 18.0 degree relative to horizontal.


Homework Equations


F=m*a


The Attempt at a Solution


I first converted the 725 grams to kilograms but then after that I am unsure of what to do. Having information about the angle is throwing me off because I don't know what equation to use.
 
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Read up again on Newton's 2nd law, the part about where it talks about the direction of the net force.
 
Well I did read that if you know the direction of acceleration, you know the direction of the net force. But I am still confused as to how this helps. Would you please explain more? Thank you!
 
What you have to do is find your force for your x-component and your force for your y-component and then find the magnitude of these. because its asking for magnitude.
so..
F_x = ma_x
and
F_y = ma_y

so for these equations obviously your mass will be the same value, but you must find your x and y component of accleration, which is an easy trig problem (draw a triangle)

you should be able to then easily solve for you F_x and F_y
once you find these you should know how to find the magnitude, its the square root of (F_x)^2 + (F_y)^2
 
But F_net =ma, where m and a are given. It's very easy, don't let the angle trick you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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