Finding Net Force on a 725 Gram Block with Given Acceleration and Angle

AI Thread Summary
To find the net force on a 725-gram block accelerating at 8.10 m/s² at an 18-degree angle, first convert the mass to kilograms. Use Newton's second law, F = m*a, to determine the force components in the x and y directions. Calculate the x and y components of acceleration using trigonometry, which involves drawing a triangle to resolve the angle. Once you have F_x and F_y, the magnitude of the net force can be found using the formula √(F_x² + F_y²). The angle does not complicate the calculation; it simply requires breaking the acceleration into components.
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Homework Statement


Find the magnitude of net force on the following object a 725 gram block that is accelerating at 8.10 m/s2 at an angle of 18.0 degree relative to horizontal.


Homework Equations


F=m*a


The Attempt at a Solution


I first converted the 725 grams to kilograms but then after that I am unsure of what to do. Having information about the angle is throwing me off because I don't know what equation to use.
 
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Read up again on Newton's 2nd law, the part about where it talks about the direction of the net force.
 
Well I did read that if you know the direction of acceleration, you know the direction of the net force. But I am still confused as to how this helps. Would you please explain more? Thank you!
 
What you have to do is find your force for your x-component and your force for your y-component and then find the magnitude of these. because its asking for magnitude.
so..
F_x = ma_x
and
F_y = ma_y

so for these equations obviously your mass will be the same value, but you must find your x and y component of accleration, which is an easy trig problem (draw a triangle)

you should be able to then easily solve for you F_x and F_y
once you find these you should know how to find the magnitude, its the square root of (F_x)^2 + (F_y)^2
 
But F_net =ma, where m and a are given. It's very easy, don't let the angle trick you.
 
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