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If I take a DC motor and put it in generator mode, what will happen if I connect a resistance at the wire ending of the DC motor? Will the motor turn slower compared to when the electric wire of the motor is connected to nothing?

What effect will the resistance have on the current flowing in the motor coil?

I know that in generator mode, mechanical energy is being converted to electrical energy. In this case, mechanical power = torque x angular velocity and electrical power=voltage x current.

I also know that V=RI+L(dI/dt)+E, and E=Kv.W. By neglecting the coil resistance R, is the voltage in the electrical power equation equals to E in generator mode?

I am kinda confused here. Please help me out.

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# Finding out Kv motor velocity constant

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