Finding peak Emf, pretty quick answer

  • Thread starter pyroknife
  • Start date
  • #1
613
3
I attached the link to the problem. Shouldn't the Vlmax be 330V? I tried entering that and it wasn't accepting my answer.
 

Answers and Replies

  • #3
613
3
Where is the link?

oh oops sorry lol! no wonder why i didn't get any replies.
 

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  • #4
798
1
When dealing with ac sources you want to be dealing with the rms voltage.
[tex]V_{peak}=\sqrt{2}V_{rms}[/tex]
 
  • #5
613
3
When dealing with ac sources you want to be dealing with the rms voltage.
[tex]V_{peak}=\sqrt{2}V_{rms}[/tex]

Well thats the 2nd part of part b where it asks for the rms Voltage. The 1st part is asking for the peak. I thought the peak was defined by emf=emfpeak * cos(wt+weird symbol) and in this case wouldn't emf peak just be 330V?
 
  • #6
gneill
Mentor
20,945
2,886
You have a series circuit (resistor and inductor), so it's a voltage divider. The peak voltage across either component must be less than the voltage supply's peak. You'll have to deal with the reactance of the inductor (or its impedance if you're familiar with that).
 

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