Finding Points of Inflection on a Curve

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The discussion focuses on finding points of inflection for the polynomial curve defined by the equation y = -3x^4 + 4x^3 + 36x^2. The second derivative, calculated as y'' = -36x^2 + 24x + 72, was set to zero to find critical points. The solutions for x were determined using the quadratic formula, yielding x = -1.1196 and x = 1.7863. Consequently, the points of inflection are identified as (-1.1196, 34.79) and (1.7863, 107.12).

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donjt81
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Hi guys... I have this problem that i need to verify. I did it but i just want one of you guys to maybe check to see if it is correct.

problem: find the points of inflection on the curve

y = -3x^4 + 4x^3 +36x^2

so first i found y'' = -36x^2 + 24x + 72 = 0
since b^2 - 4ac is not a perfect square i had to use the formula
x = [ -b + sqrt(b^2 - 4ac) ]/2a
and
x = [ -b - sqrt(b^2 - 4ac) ]/2a

by using these i get the values of x as
x = -1.1196
and x = 1.7863

so the points of inflection are (-1.1196, 34.79) and (1.7863, 107.12)

Thanks in advance
 
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Perfect :).
 

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