Finding potential difference to stop a proton

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kamehamehaaa
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Homework Statement


On attachment. Part B only. I got C.


Homework Equations


mass of proton is 1.673*10^-27
q0 = 1.60*10^-19


The Attempt at a Solution



For part B I thought I could divide the intial speed by 2 and plug it back into the energy conservation equation:

.5mv^2 + q0V1 = .5mv^2 + q0V2 and solve for (V1 - V2) which would be the potential difference but it doesn't seem to work.
 
Attachments
  • Screenshot of an online homework system showing Problem 20.20 with Parts A, B and C; Part A answer 470 V marked correct, Part B and C answers entered as 1.1 x 10^2 and 1.2 x 10^2 and marked Try Again.
    20.20 part b c.JPG
    42.7 KB · Views: 439
That should work just fine. (Show what you actually did.)

Another way to look at it is: By what fraction must the total energy be decreased to bring the speed to half its initial value? Compare that with the answer you got for part A.