Finding potential difference in a very long hollow cylinder

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SUMMARY

The discussion focuses on calculating the electric potential difference in a long hollow cylinder with inner radius A and outer radius B, given a uniform charge density p. The user applied Gauss's Law to determine the electric field, resulting in an expression of pV/E0 after integration. However, the correct potential difference is identified as -p/2E0 (4A^2/2 - A^2/2 - A^2ln2), indicating a miscalculation in the integration process. The user seeks clarification on their error in deriving the potential difference.

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aldofbg
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A very long hollow cylinder has inner radius A and outer radius B. It has a known unit charge per unit volume p. Find the difference in the electric potential a point on the axis and a point a distance A+D assuming A+D<B
The diagram is in the url. It is #3

http://people.physics.tamu.edu/etanya/P208/exam_2_2014.pdf

I used Gauss law to find the Electric field at a point 'R'. I got pV/E0 then I integrated this from 0 to A+D and I got the answer p[A+D]^2/E0 though this isn't the answer. Could someone explain what I did wrong?
The correct answer is -p/2E0 (4A^2/2 - A^2/2 - A^2ln2)
 
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aldofbg said:
I got pV/E0
Please post your working to that point.
 

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