Finding relativistic mass and energy of an electron

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SUMMARY

The discussion focuses on calculating the relativistic mass and energy of an electron accelerated to 0.5 times the speed of light. The calculations involve using the equations for kinetic energy (K = mv²/2) and total energy (E = mc²). The correct relativistic mass is derived using the Lorentz factor (gamma), defined as γ = 1/√(1 - v²/c²), leading to a final relativistic mass of approximately 7.88 x 10^-31 kg and total energy of approximately 9.45 x 10^-14 J. The kinetic energy is calculated as 1.26 x 10^-14 J, confirming the relationships between rest mass, relativistic mass, and energy.

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  • Understanding of relativistic physics concepts, specifically mass-energy equivalence.
  • Familiarity with the Lorentz factor (gamma) and its application in relativistic calculations.
  • Knowledge of basic physics equations for kinetic energy and total energy.
  • Ability to perform calculations involving scientific notation and unit conversions.
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  • Study the derivation and implications of the Lorentz factor (gamma) in special relativity.
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AlexPilk
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Homework Statement



A resting electron was sped up to 0.5 of the speed of light. Find:
A. relativistic mass of the electron,
B. total energy of the electron,
C. kinetic energy of the electron.

Homework Equations


K = mv^2/2
E=mc^2

The Attempt at a Solution


Let’s first find the kinetic energy:
K = m*v^2/2
K = (9.1*10^-31*0.25*9*10^16)/2 = 1.02375*10^-14 J

Now we should find relativistic mass using E=mc^2.
m(rel) = E/c^2 = (1.02375*10^-14)/(9*10^16) = 1.1375*10^-31 kg

Total energy must be = m(rest)*c^2
Then E(total) = 9.1*10^-31*9*10^16 = 8.19*10^-14 J

Is this solution correct?
And I suppose potential energy = 8.19*10^-14 - 1.02375*10^-14 = 7.16625*10^-14 ? :)
 
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No, that is not correct. Do you have an equation with rest mass and Gamma (which is a relationship that crops up a lot in relativistic formula)?
 
rpthomps said:
No, that is not correct. Do you have an equation with rest mass and Gamma (which is a relationship that crops up a lot in relativistic formula)?
I'm not sure what equation you mean. I found p = mv*gamma, but I don't understand what gamma means there.
 
This is gamma

##\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}##
 
You were never taught this?
 
rpthomps said:
You were never taught this?
I have a ton of stuff to figure out by myself in a short period of time, so sorry for stupid questions :( I don't remember anything about relativistic mass from school.
So gamma is also relativistic mass/rest mass?
 
Its not a stupid question, I am just wondering what you know about mass at relativistic speeds. Check out the article I sent, there is a ratio embedded in there that you will find useful. :)
 
rpthomps said:
Its not a stupid question, I am just wondering what you know about mass at relativistic speeds. Check out the article I sent, there is a ratio embedded in there that you will find useful. :)
Ok, then m(rel) = gamma*m(rest)
gamma = sqrt(1-0.25) = sqrt(0.75)
m(rel) = sqrt(0.75)*9.1*10^-31 = 7.88*10^-31

Is it correct now?
 
  • #10
Gamma is almost like a way of translating mass/lengths/time from the ordinary or Newtonian way of thinking of life to the relativistic way... It's usually a multiplier of some kind.
 
  • #11
AlexPilk said:
Ok, then m(rel) = gamma*m(rest)
gamma = sqrt(1-0.25) = sqrt(0.75)
m(rel) = sqrt(0.75)*9.1*10^-31 = 7.88*10^-31

Is it correct now?

You are close. It should be m_electron/sqrt(0.75)
 
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  • #12
rpthomps said:
You are close. It should be m_electron/sqrt(0.75)
Hm, but why? On wikipedia the equation is m(rel)/m(rest) = gamma, so gamma*m(rest) = m(rel)
 
  • #13
rpthomps said:
This is gamma

##\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}##

Mass increases as speed increases
 
  • #14
rpthomps said:
Mass increases as speed increases
Right, got it. So then I should plug in relativistic mass as m into K = mv^2/2 and E=mc^2 and get the kinetic and total energies?
Then m = 9.1*10^-31/sqrt(75) = 1.05 * 10^-30
Total energy E = 1.05*10^-30*9*10^16 = 9.45*10^-14
Kinetic energy K = (1.05*10^-30*0.25*9*10^8)/2 = 1.18*10^-22

Or am I wrong again?
 
  • #15
Oh, looked it up. KE = mc^2 - m0c^2 = 1.05*10^-30*9*10^16 - 9.1*10^-31*9*10^16 = 1.26*10^-14 J
Now I have to figure what "total energy" means.
KE = Total energy - Potential energy, so I suppose m(rel)*c^2 = 9.45*10^-14 is total energy like I wrote in the previous message? I hope it's correct now? :)
 

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