Finding Remainder of Shaded Squares in 6x4 Grid

Click For Summary

Homework Help Overview

The problem involves a 6 x 4 grid where 12 out of 24 squares need to be shaded, with the condition that each row contains exactly two shaded squares and each column contains three shaded squares. The goal is to find the number of valid configurations and determine the remainder when this number is divided by 1000.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to explore symmetry and possible case divisions to solve the problem. There is a mention of needing to find an equivalent problem or approach.

Discussion Status

Participants are discussing the appropriateness of posting in the Homework Help forum, with some suggesting that the original poster might find better guidance in a different forum. There are hints about looking at the solution without fully reading it, indicating a desire to engage with the problem while avoiding direct answers.

Contextual Notes

Some participants express concern about the relevance of the post to the Homework Help forum, suggesting that the original poster may not be currently enrolled in math classes and questioning the nature of their inquiries.

ehrenfest
Messages
2,001
Reaction score
1

Homework Statement


In a 6 x 4 grid (6 rows, 4 columns), 12 of the 24 squares are to be shaded so that there are two shaded squares in each row and three shaded squares in each column. Let be the number of shadings with this property. Find the remainder when is divided by 1000.

There is a picture at this link if you do not understand the question:

http://www.artofproblemsolving.com/Wiki/index.php/2007_AIME_I_Problems#Problem_8


Homework Equations





The Attempt at a Solution


So, somehow we need to divide this into case or find some equivalent problem or something. Symmetry might help us since reflection about the middle horizontal line and reflection about the middle vertical line will preserve the property. Also, inversion of color will preserve the property. So the answer (before you take the remainder) must be a multiple of two. Hmmm...I am out of ideas.
 
Last edited by a moderator:
Physics news on Phys.org
erhenfest, the problem has a solution link. Why don't you click it if you are out of ideas? What's the point to posting it here? This is a "Homework Help" forum, I don't think this qualifies.
 
Dick said:
erhenfest, the problem has a solution link. Why don't you click it if you are out of ideas?

If there were a hint button, I would click on it but there isn't and I don't want to give up completely.

Dick said:
What's the point to posting it here? This is a "Homework Help" forum, I don't think this qualifies.


Almost none of my questions are homework (in fact I am not even taking any math classes this summer). This is also a "coursework forum". But anyway do you think it would be better to post these in "General Math"?
 
That's a reasonable point, but yes, you should probably post them elsewhere. You've already posted one of these without an explicit pointer to the source, though you did quote the AIME reference. Is there a "Problem Practice" forum to discuss problem solving strategies?
 
You might try this. Just look at the solution for a little bit. Don't read the whole thing through. That constitutes a hint along the lines to proceed without telling you the whole story. I've done it when practicing.
 
cristo suggests you confine these things to a single thread in "General Math" to avoid cluttering up the HH forums.
 
Dick said:
cristo suggests you confine these things to a single thread in "General Math" to avoid cluttering up the HH forums. He also suggests the following discussion site about these questions http://www.artofproblemsolving.com/F...p?c=182&cid=45

I moved the discussion to GD: https://www.physicsforums.com/showthread.php?t=237287

The link you gave does not work.
 
Last edited by a moderator:

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
1
Views
2K
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K