Finding Resistance and Inductance of solenoid

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SUMMARY

The discussion focuses on calculating the resistance, inductance, and time constant of a solenoid constructed with five layers of 0.30 mm diameter copper wire wrapped around a toilet paper roll. The resistance is determined to be 62.3 ohms, calculated using the formula R = ρL/A, where ρ is the resistivity of copper (1.7 x 10^-8 ohm-meter). The inductance is calculated using the formula L = μ₀n²V, where n is the number of turns per unit length of the solenoid. Participants clarify that n should be derived from the total number of turns divided by the length of the solenoid, not the length of the wire.

PREREQUISITES
  • Understanding of solenoid physics and electromagnetic principles
  • Familiarity with electrical resistance calculations using R = ρL/A
  • Knowledge of inductance calculations using L = μ₀n²V
  • Basic geometry for calculating circumference and area
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  • Research the concept of solenoid inductance and its applications in circuits
  • Learn how to calculate the number of turns in a solenoid based on its dimensions
  • Explore the impact of wire gauge on resistance and inductance in solenoids
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teknodude
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The inductance of the solenoid determines the time it takes to establish this current. Find the inductance,the resistance, and the time constant of a solenoid that is constructed by wrapping five “tightly wound” (i.e., wire-against-wire like this ) layers of 0.30 mm diameter copper wire on a toilet paper roll that is 11.5 cm long and 4.3 cm in diameter. (The resistivity of copper is 1.7 x 10^8 ohm-meter. Hint: Find the number of “turns” in the solenoid. You may assume that the diameter of each turn is 4.3 cm.)

radius of copper wire= 1.5x10^-4 m
radius of toilet paper roll= 0.0215m
length of TP roll= 0.115m

I'm thinking that i need to find resistance first, but what's confusing me is that the toilet paper roll is being wrapped by layers of copper wire. So I might have to take into account of the added thickness of the toilet paper roll.
I know I have to use the following equation:
R=\frac{\rho L} {A} <br /> rho is the resistivity, A=cross sectional area, L=length

The hint says to find the number of “turns” in the solenoid. I'm thinking that in order to find the # of turns is to take the given length and divide by the circumferance of the TP roll.
# of turns=\frac{0.115} {2\pi*1.5*10^-4} <br />
But then how do i find the length of the copper wire?


I know the answer for the resistance is 62.3 ohms. I tried working backwards and found that the L=259meters. I can't seem to get that length... what i am i doing wrong
 
Last edited:
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The number of turns will be the length of the roll divided by the diameter of the wire times 5 for the 5 layers. The length of each turn is one circumference of the roll.
 
Last edited:
Thank you olderdan

Also for calculating the inductance, I am using this equation
L=\mu_0n^2V <br />

n is the number of turns per unit length. Do i just divide the number of turns that i got from the first part by the length of the wire to get n?
 
Last edited:
teknodude said:
Thank you olderdan

Also for calculating the inductance, I am using this equation
L=\mu_0n^2V <br />

n is the number of turns per unit length. Do i just divide the number of turns that i got from the first part by the length of the wire to get n?

It is the number of terns per unit length of the solenoid, not per unit length of the wire.
 

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