Finding Resistance Between A & B: Solved

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Homework Help Overview

The discussion revolves around calculating the resistance between two points, A and B, in a circuit containing multiple resistors with specified values. Participants are exploring the concepts of equivalent resistance and circuit combinations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants express confusion about the distinction between equivalent resistance and the resistance between points A and B. Others suggest using series and parallel combination rules to simplify the circuit.

Discussion Status

The discussion includes attempts to clarify the problem and explore different methods for calculating resistance. Some participants have provided guidance on how to approach the problem, while others emphasize the importance of understanding the reasoning behind the calculations rather than simply providing answers.

Contextual Notes

There is a note of concern regarding the provision of direct answers versus guiding participants to develop their understanding of the problem-solving process.

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[SOLVED] Finding Resistance

Homework Statement


A number of resistors of values R1 = 3.8 Ω, R2 = 80.0 Ω, and R3 = 20.0 Ω are connected as shown in the figure. What is the resistance between points A and B?


Homework Equations





The Attempt at a Solution



Im confused because all I've been calculating is the equivalent resistance, what is the difference between the two?
 

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n77ler said:

Homework Statement


A number of resistors of values R1 = 3.8 Ω, R2 = 80.0 Ω, and R3 = 20.0 Ω are connected as shown in the figure. What is the resistance between points A and B?


Homework Equations





The Attempt at a Solution



Im confused because all I've been calculating is the equivalent resistance, what is the difference between the two?


They are just asking for the equivalent resistance of that network, as seen at the entry points A & B. Just use your series & parallel combination rules to reduce the network to a single (equivalent) resistor between A & B, and you will have your answer.
 
ok thank-you
 
The Four R1 and R3 are in series thus those five resistors to the right can be combined by adding the value...(4*3.8+20)=35.2Ω
That resistance is in parallel with the R2 thus the combination of the five and this resistor is equal to 1/(1/35.2+1/80) = 24.4Ω (3sf)
Now the total becomes this plus 2*R1

Total = 24.4+3.8*2 = 32.0Ω (3s.f.)

Just incase you were still stuck, that and I like to go back to some easy electronics now and again to remind me that my head hasn't exploded :)
 
You shouldn't give out the answers. We're not here to give solutions, but rather how to figure out a problem.
 
My Apologies, I was only going from what I saw in the rest of the forum.
 

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