Finding rotational inertia of a yo-yo

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SUMMARY

The discussion focuses on calculating the rotational inertia of a yo-yo device used to lift a 30kg box. Given parameters include an outer radius (R) of 0.50m, a hub radius (r) of 0.20m, and a constant horizontal force (F) of 140N applied to a rope. The box experiences an upward acceleration of 0.80 m/s². By applying Newton's 2nd law to both the yo-yo and the box, one can derive the rotational inertia of the device about its axis of rotation.

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A yo-yo shaped device mounted on a horizontal frictionless axis is used to lift a 30kg as shown. The outer radius R of the device is 0.50m, and the radius r of the hub is 0.20 m. Wen a constant horizontal force F of magnitude 140N is applied to a rope wrapped around the outside of the device, the box, which is suspended from arope wrapped around the hub, has an upward acceleration of magnitude 0.80 m/s^2. What is the rotational inertia of the device about its axis of rotation?

http://img438.imageshack.us/img438/7076/problemci9.jpg
 
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Well... where's your work?

Hint: Apply Newton's 2nd law to both the yo-yo and the box. Take advantage of the information given and you'll be able to solve for the rotational inertia.
 

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