Finding Series Solutions Using Method of Frobenius

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Homework Statement



Using method of Frobenius, find a series solution to the following differential equation:

[tex] x^2\frac{d^2y(x)}{dx^2} + 4x\frac{dy(x)}{dx} + xy(x) = 0 [/tex]

Homework Equations



[tex]y(x) = \sum_{n = 0}^\infty C_{n} x^{n + s}[/tex]


The Attempt at a Solution



[tex] y(x) = \sum_{n = 0}^\infty C_{n} x^{n + s}[/tex]
[tex] \frac{dy(x)}{dx} = \sum_{n = 0}^\infty C_{n} (n + s) x^{n + s - 1}[/tex]
[tex] \frac{d^2 y(x)}{dx^2} = \sum_{n = 0}^\infty C_{n} (n + s) (n + s - 1) x^{n + s - 2}[/tex]

Therefore, by substituting, I get:

[tex] x^2\frac{d^2y(x)}{dx^2} = \sum_{n = 0}^\infty C_{n} (n + s) (n + s - 1) x^{n + s}[/tex]
[tex] 4x\frac{dy(x)}{dx} = \sum_{n = 0}^\infty 4C_{n} (n + s) x^{n + s}[/tex]
[tex] xy(x) = \sum_{n = 0}^\infty C_{n} x^{n + s + 1} = \sum_{n = 1}^\infty C_{n - 1} x^{n + s} \rightarrow n + 1 = m \leftrightarrow n = m - 1, n \geq 0, m \geq 1[/tex]

Combining all terms, I get:

[tex] C_{0}((s + 0) (s + 0 - 1) + 4(s + 0))x^s + \sum_{n = 1}^\infty [C_{n} (n + s) (n + s + 3) + C_{n - 1}] x^{n + s}[/tex]

Assuming [itex]C_{0}[/itex] is not 0, I get:

[tex] C_{0}(s(s + 3)) = 0[/tex]

and...

[tex] C_{n} (n + s) (n + s + 3) + C_{n - 1} = 0[/tex]

Now, with the assumption is that [itex]C_{0}[/itex] is not 0, I conclude that:

[tex] <br /> s(s + 3) = 0, s = 0 , -3<br /> [/tex]

Now... So far, so good. The problem is within the generating terms.

[tex] C_{n} (n + s) (n + s + 3) + C_{n - 1} = 0[/tex]

This has to be zero at all times, meaning:

[tex] C_{n} (n + s) (n + s + 3) = - C_{n - 1}[/tex]

Therefore:

[tex] C_{n} = - \frac{C_{n - 1}}{(n + s) (n + s + 3)}[/tex]

So what's the problem? You see, if we assume s = -3, and [itex]C_{0}[/itex] is not 0, then we got a problem at [itex]n = 3, s = -3[/itex] as that will mean the whole equation will explode. This means [itex]C_{0}[/itex], [itex]C_{1}[/itex], [itex]C_{2}[/itex] are all zero, with no information about [itex]C_{3}[/itex]

Am I doing it right? I am having my doubts.
 
Last edited:
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Mark44 said:
Shouldn't your DE be
[tex]x^2\frac{d^2 y(x)}{dx^2} + 4x\frac{d y(x)}{d x} + xy(x) = 0[/tex]
?

IOW, the 2nd derivative in the first term, and derivatives intead of partial derivatives?

Take a look at this wikipedia article - http://en.wikipedia.org/wiki/Frobenius_method

I wasn't done typing the problem, and my attempt at it.

Trivial errors are all fixed by now. That aside...

I still don't see how much sense I can get out of the situation above.
 
I guess this problem doesn't need any more attention.

My understanding is that Method of Frobenius may be of help to find a solution to the DEQ, but it may not be able to provide all the solutions.

In this case, s = -3 doesn't provide anything useful, for instance. s = 0 is the only sensible choice, in other words.