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Homework Statement
Using method of Frobenius, find a series solution to the following differential equation:
[tex] x^2\frac{d^2y(x)}{dx^2} + 4x\frac{dy(x)}{dx} + xy(x) = 0 [/tex]
Homework Equations
[tex]y(x) = \sum_{n = 0}^\infty C_{n} x^{n + s}[/tex]
The Attempt at a Solution
[tex] y(x) = \sum_{n = 0}^\infty C_{n} x^{n + s}[/tex]
[tex] \frac{dy(x)}{dx} = \sum_{n = 0}^\infty C_{n} (n + s) x^{n + s - 1}[/tex]
[tex] \frac{d^2 y(x)}{dx^2} = \sum_{n = 0}^\infty C_{n} (n + s) (n + s - 1) x^{n + s - 2}[/tex]
Therefore, by substituting, I get:
[tex] x^2\frac{d^2y(x)}{dx^2} = \sum_{n = 0}^\infty C_{n} (n + s) (n + s - 1) x^{n + s}[/tex]
[tex] 4x\frac{dy(x)}{dx} = \sum_{n = 0}^\infty 4C_{n} (n + s) x^{n + s}[/tex]
[tex] xy(x) = \sum_{n = 0}^\infty C_{n} x^{n + s + 1} = \sum_{n = 1}^\infty C_{n - 1} x^{n + s} \rightarrow n + 1 = m \leftrightarrow n = m - 1, n \geq 0, m \geq 1[/tex]
Combining all terms, I get:
[tex] C_{0}((s + 0) (s + 0 - 1) + 4(s + 0))x^s + \sum_{n = 1}^\infty [C_{n} (n + s) (n + s + 3) + C_{n - 1}] x^{n + s}[/tex]
Assuming [itex]C_{0}[/itex] is not 0, I get:
[tex] C_{0}(s(s + 3)) = 0[/tex]
and...
[tex] C_{n} (n + s) (n + s + 3) + C_{n - 1} = 0[/tex]
Now, with the assumption is that [itex]C_{0}[/itex] is not 0, I conclude that:
[tex] <br /> s(s + 3) = 0, s = 0 , -3<br /> [/tex]
Now... So far, so good. The problem is within the generating terms.
[tex] C_{n} (n + s) (n + s + 3) + C_{n - 1} = 0[/tex]
This has to be zero at all times, meaning:
[tex] C_{n} (n + s) (n + s + 3) = - C_{n - 1}[/tex]
Therefore:
[tex] C_{n} = - \frac{C_{n - 1}}{(n + s) (n + s + 3)}[/tex]
So what's the problem? You see, if we assume s = -3, and [itex]C_{0}[/itex] is not 0, then we got a problem at [itex]n = 3, s = -3[/itex] as that will mean the whole equation will explode. This means [itex]C_{0}[/itex], [itex]C_{1}[/itex], [itex]C_{2}[/itex] are all zero, with no information about [itex]C_{3}[/itex]
Am I doing it right? I am having my doubts.
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